Which of the following has the correct name for either the acid or base

A sample of potassium phosphate octahydrate (K3PO4•8H2O) is heated until 7.93 grams of water are released. How many grams did th

Gekata [30.6K]

The original sample of potassium phosphate octahydrate had a mass of 19.6 grams. When it was heated, it released 7.93 grams of water.

Further Explanation:

For every mole of the compound potassium phosphate octahydrate, there are 8 moles of water of hydration which can be removed from the crystal by heating without altering the chemical composition of the substance.

To determine how much original sample was used, the amount of water released upon heating may be used as well as the mole ratio of the water of hydration with the compound itself following the steps below:

Convert mass of water released to moles.
Use the mole ratio of water of hydration to the compound (8 mol water for every mol of potassium phosphate octahydrate) to get the moles of original sample.
Convert the moles of original sample to grams.

STEP 1: Convert 7.93 g water to moles.

$moles \ of\ H_{2}O \ = 7.93 \ g \ H_{2}O \ (\frac{1 \ mol \ H_{2}O}{18.00 \ g \ H_{2}O})\\\boxed {moles \ of \ H_{2}O \ = 0.4406 \ mol}$

STEP 2: Calculate the moles of original sample using the mole ratio: 1 mol K3PO4 8H2O : 8 mol H2O.

$moles \ of \ K_{3}PO_{4}\ 8H_{2}O \ = 0.4406 \ mol \ H_{2}O \ (\frac{1 \ mol \ K_{3}PO_{4}\ 8H_{2}O \ }{8 \ mol \ H_{2}O})\\\\\boxed {moles \ of \ K_{3}PO_{4}\ 8H_{2}O \ = 0.0551 \ mol}$

STEP 3: Convert the moles of original sample to mass.

$mass \ of \ K_{3}PO_{4}\ 8H_{2}O = 0.0551 \ mol \ K_{3}PO_{4}\ 8H_{2}O \ (\frac{356.3885 \ g}{1 \ mol\ K_{3}PO_{4}\ 8H_{2}O})\\ mass \ of \ K_{3}PO_{4}\ 8H_{2}O \ = 19.637 \ g$

Following the significant figures of the given, the final answer should be:

$\boxed {mass \ of \ K_{3}PO_{4}\ 8H_{2}O = 19.6 \ g}$

Learn More:

Learn more about water of hydration brainly.com/question/6053815
Learn more about mole conversion brainly.com/question/12979299
Learn more about percent hydrate brainly.com/question/12398621

Keywords: water of hydration, hydrate

4 0

3 years ago

Read 2 more answers

I need help on #2 a and b. please explain steps and answer

Vaselesa [24]

I think A. o2 is oxygen, h202 is a clear liquid like bleach, And H20 is water lol :P

4 0

3 years ago

Which of these redox reactions is spontaneous as written?

natta225 [31]

The answer of this question is A

7 0

3 years ago

The value of ΔH° for the reaction below is -126 kJ. The amount of heat that is released by the reaction of 25.0 g of Na2O2 with

Alexus [3.1K]

Answer:

20.2 kJ

Explanation:

Based on the information in the reaction, the amount of heat released per mole of Na₂O₂ (the molar enthalpy) is calculated as follows:

126 kJ / 2 mol = 63 kJ/mol Na₂O₂

The number of moles in 25.0g of Na₂O₂ must be calculated using the molecular weight of Na₂O₂ (77.978 g/mol):

(25.0 g)/(77.978 g/mol) = 0.32060 mol Na₂O₂

Thus, the heat released will be:

(63 kJ/mol)(0.32060 mol) = 20.2 kJ

6 0

4 years ago

Read 2 more answers

Plz help with this.....☺

Elodia [21]

Answer:

There is this property called CATENATION which is basically the tendency of the atoms to bind to eachother. It is the MOST in the carbon after that silicon.

So the answer should Carbon atoms bond together to form groups of compounds.

8 0

3 years ago