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2 years ago

If only one-fourth the amount of brown sugar in the recipe were used, how much brown sugar would be used?

1 answer:

7 0

3/4 or 4/4 would be the answer because if you use 1/4 out of 4/4 you would either have an answer of 3/4, 4/4 or 1. The 1 because 4/4 is equal to 1.

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A sample of gas is placed into an enclosed cylinder and fitted with a movable piston. Calculate the work (in joules) done by the

Nuetrik [128]

Explanation:

here is the answer. Feel free to ask for more chem help

6 0

2 years ago

in the laboratory a student dilute 13.3 ml of a 10.8 m hcl solution to a total of 300.0 ml what is the concentration of the dilu

krek1111 [17]

<u>Answer:</u> The concentration of the diluted solution is 0.4788M

<u>Explanation:</u>

To calculate the concentration of the diluted solution, we use the following equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of HCl solution

$M_2\text{ and }V_2$ are the molarity and volume of the diluted HCl solution.

We are given:

$M_1=10.8M\\V_1=13.3mL\\M_2=?M\\V_2=300mL$

Putting values in above equation, we get:

$10.8\times 13.3=M_2\times 300\\\\M_1=0.4788M$

Hence, the concentration of the diluted solution is 0.4788M

6 0

3 years ago

If you are administering an insulin dose of 90.0 mg from a bottle at a concentration of 10.0 mg/mL,

Fiesta28 [93]

Answer:

9 mL.

Explanation:

Dosage of insulin is 90 mg

The concentration of insulin is 10 mg/mL

We need to find how many milliliters of the solution do you need to give the patient. It can be calculated as follows :

$x=\dfrac{90\ \text{mg}}{10\dfrac{\text{mg}}{\text{mL}}}\\\\x=\dfrac{9}{1}\ \text{mL}$

So, 9 mL of the solution is to be given to the patient.

4 0

2 years ago

1. Sometimes scientists need to be able to replicate the results of a scientific experiment. Explain in what situation(s) this w

Andrej [43]

I need this also I’m just here for points

4 0

3 years ago

G you have 57.0 ml of a 0.400 m stock solution that must be diluted to 0.100 m. assuming the volumes are additive, how much wate

Amanda [17]

Answer:
added water = 171 ml

Explanation:
Assuming volumes are additive, the rule that we will use to solve this question is:
M1V1 = M2V2
where:
M1 is the initial concentration = 0.4 m
V1 is the initial volume = 57 ml
M2 is the final concentration = 0.1 m
V2 is the final volume that we want to calculate
Substitute with the given in the above equation to get V2 as follows:
M1V1 = M2V2
(0.4)(57) = (0.1)V2
22.8 = 0.1V2
V2 = 228 ml

Now, the final volume is equal to the initial volume plus the amount of added water. So, to get the amount of added water, we will subtract the initial volume from the final volume as follows:
V2 = V1 + added water
228 = 57 + added water
added water = 228 - 57 = 171 ml

Hope this helps :)

3 0

3 years ago