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ExtremeBDS [4]
1 year ago
13

Can anyone help me figure this out

Chemistry
1 answer:
MA_775_DIABLO [31]1 year ago
8 0

Answer:

go with the fourth one because I did that one

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Fill in the missing data point. Show all calculations leading to an answer.
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Answer:  

1090 mmHg  

Explanation:  

We know that with gases we must use a Kelvin temperatures, so let’s try a plot of pressure against the Kelvin temperature.  

We can create a table as follows  

<u>t/°C</u>  <u>T/K</u>  <u>p/mmHg</u>  

  10   283      726  

  20  293      750  

  40   313      800  

  70  343      880  

100  373       960  

150  423        ???  

I plotted the data and got the graph in the figure below.  

It appears that pressure is a linear function of the Kelvin temperature.  

y = mx + b  

where x is the slope and b is the y-intercept.

===============

<em>Calculate the slope  </em>

I will use the points (275, 700) and (380, 975).  

Slope = Δy/Δx = (y₂ - y₁)/(x₂ -x₁) = (975 -700)/(380 – 275) = 275/105 = 2.619  

So,  

y = 2.619x + b  

===============

<em>Calculate the intercept </em>

When x = 275, y = 700.  

700 = 2.619 × 275 + b  

700 = 720 + b     Subtract 720 from each side and transpose.  

b = -20  

So, the equation of the graph is  

y = 2.619x -20  

===============

<em>Calculate the pressure</em> at 423 K (150°C)  

y = 2.619 × 423 - 20  

y = 1110 - 20  

y = 1090

At 150 °C, the pressure 1090 mmHg.  

The point is approximately at the position of the black dot in the graph.  

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