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svetlana [45]
3 years ago
15

If two clear liquids are mixed and a precipitate formed, what has probably happened?

Chemistry
2 answers:
White raven [17]3 years ago
8 0
It will probably turned into a gumy
yaroslaw [1]3 years ago
7 0
A chemical reaction has occurred and water and a salt has formed
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Consider the following reaction: SO2Cl2(g)⇌SO2(g)+Cl2(g) A reaction mixture is made containing an initial [SO2Cl2] of 2.2×10−2M
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The value of equilibrium constant is equal to the quotient of the products raised to its stoichiometric coefficient over the reaction's reactants raised to its respective stoichiometric coeff. The equation is Kc=[SO2][Cl2]/[SO2Cl2]= [1.3*10^-2][1.3*10^-2]/[2.2*10^-2-<span>1.3*10^-2]=0.0188. The final answer is Kc=0.0188.</span>
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3 years ago
What type of heat transfer is a beaker on a hot plate an example of?
sesenic [268]

Heat transfer to a beaker on a hot plate is an example of conduction.

Explanation:

Conduction is a process where heat is transferred from one particle to another particle. Conduction is mainly possible in case of solids.In case of solids the atoms as well as the molecules are tightly packed through which the kinetic energy can easily pass. Conduction takes place when both the objects are touching each other. But in case of liquids molecules are loosely packed as a result convection takes place.

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Sodium (na), atomic number 11, has a tendency to lose an electron in the presence of chlorine. after losing the electron, na has
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Which of these is a bacteria?<br><br> E-coli<br> HIV<br> Yeast<br> Zika
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5 0
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Carbon dioxide and water react to form methanol and oxygen, like this:
fredd [130]

Answer:

24x10³

Explanation:

2CO₂(g) + 4H₂O(g) → 2CH₃OH(l) + 3O₂ (g)

The equilibrium constant for this reaction is:

Kc = \frac{[O_2]^3}{[CO_2]^2[H_2O]^4}

The expression of [CH₃OH] is left out as it is a pure liquid.

Now we <u>convert the given masses of the relevant species into moles</u>, using their <em>respective molar masses</em>:

  • CO₂ ⇒ 3.28 g ÷ 44 g/mol = 0.0745 mol CO₂
  • H₂O ⇒ 3.86 g ÷ 18 g/mol = 0.214 mol H₂O
  • O₂ ⇒ 2.80 g ÷ 32 g/mol = 0.0875 mol O₂

Then we calculate the concentrations:

  • [CO₂] = 0.0745 mol / 7.5 L = 0.0099 M
  • [H₂O] = 0.214 mol / 7.5 L = 0.0285 M
  • [O₂] = 0.0875 mol / 7.5 L = 0.0117 M

Finally we <u>calculate Kc</u>:

  • Kc = \frac{0.0117^3}{0.0099^2*0.0285^4} = 24x10³

3 0
3 years ago
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