Question

At constant temperature the pressure on a 6.0 L sample of a gas is reduced from 2.0 atm to 1.0 atm. What is the new volume of the gas sample?

Answer 1

Answer:

V = 12 L

Explanation:

In order to know this, we can use the ideal gas equation which is:

PV = nRT (1)

Where:

P: Pressure

V: Volume

n: moles

R: gas constant

T: Temperature

Now, we don't know the temperature or the mole, but the problem states that the temperature is constante, so, T1 = T2 = T.

As is the same gas, we can asume the moles are the same, so n1 = n2 = n. And the gas constant is always the same value, therefore:

P1V1 = nRT

P2V2 = nRT

The general equation would be:

P1V1 = P2V2 (2)

This is known as the Boyle's law which is a relation concerning the compression and expansion of a gas at constant temperature.

So, we use the above expression and replace the data to solve for V2:

V2 = P1V1/P2

V2 = 6 * 2 / 1

V2 = 12 L

This is the new volume, when the gas is compressed.

Answer 2

P1V1=P2V2, so P1V1/P2=V2.
2atm x 6.0 L/1.0 atm = 12.0 L
The new volume would be 12.0 Liters