Answer:
108 extended days
Explanation:
Regular school hours a day = 6 hr
No. of school days to make up by extending the regular hours = 3 days
Amount of time added to the regular hours of school = 10 min
No. of extended school days to make up the 3 school days by following the above mentioned criteria be x.
Time of school hours in 3 days =
are required to make up 3 days of school having 6 hours of regular timing with 10 minutes of add-on time each day.
The question is incomplete. The complete question is :
The Rocket Club is planning to launch a pair of model rockets. To build the rocket, the club needs a rocket body paired with an engine. The table lists the mass of three possible rocket bodies and the force generated by three possible engines.
A 4-column table with 3 rows. The first column labeled Body has entries 1, 2, 3. The second column labeled Mass (grams) has entries 500, 1500, 750. The third column labeled Engine has entries 1, 2, 3. The fourth column labeled Force (Newtons) has entries 25, 20, 30.
Based on Newton’s laws of motion, which combination of rocket bodies and engines will result in the acceleration of 40 m/s2 at the start of the launch?
Body 3 + Engine 1
Body 2 + Engine 2
Body 1 + Engine 2
Body 1 + Engine 1
Solution :
Given :
Body Mass (gram) Engine Force (newtons)
1 500 1 25
2 1500 2 20
3 750 3 30
The body 1 has a mass of 500 gram which is equal to 0.5 kg
And engine 2 has a force of 20 newtons.
We know that according to Newton's laws of motion,
Force = mass x acceleration
20 = 0.5 x acceleration
Acceleration
Therefore, based on laws of motion of Newton, the Body 1 + Engine 2 combination of the rocket bodies and engines will result in an acceleration of at the start of the launch.
Answer:
a. B = 0.20T
b. u = 17230.6 J/m³
c. E = 0.236J
d. L = 5.84*10^-5 H
Explanation:
a. In order to calculate the magnetic field in the solenoid you use the following formula:
(1)
μo: magnetic permeability of vacuum = 4π*10^-7 T/A
n: turns of the solenoid = 460
L: length of the solenoid = 25.0cm = 0.25m
i: current = 90.0A
You replace the values of the parameters in the equation (1):
The magnetic field in the solenoid is 0.20T
b. The magnetic permeability of air is approximately equal to the magnetic permeability of vacuum. To calculate the energy density in the solenoid you use:
The energy density is 17230.6 J/m³
c. The total energy contained in the solenoid is:
(2)
V is the volume of the solenoid and is calculated by assuming the solenoid as a perfect cylinder:
A: cross-sectional area of the solenoid = 0.550 cm^2 = 5.5*10^-5m^2
Then, the energy contained in the solenoid is:
The energy contained is 0.236J
d. The inductance of the solenoid is calculated as follow:
The inductance of the solenoid is 5.84*10^-5 H