The two possible angles obtained by using the qudratic equation are;
θ
= 15.10° and θ2 = 73.51°
Given, speed of water = 
= 50ft/s
For the motion along x direction, time period can be calculated as follows:
35 = (50 × cosθ) t
t = 0.64 / cosθ
For the motion in y direction, an equation can be obtained as follows:
θ) 
Plugging in the values we get:
θ) 
-20 = -32tanθ - 10.304
θ
Upon solving the above quadratic equation, we get,
tanθ = 0.27 , -3.38
Therefore,
tanθ = 0.27
θ = 15.10°
and, tanθ
= -3.38
θ = 73.51
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Answer:
Correct answer: Ek = 2,028.6 J
Explanation:
Ek = m v²/2 = 0.023 · 220² = 0.023 · 176,400/2 = 2,028.6 J
God is with you!!!
That equation is Newton's universal law of gravitation. ... Any two masses exert equal-and-opposite gravitational forces on each other. If we drop a ball, the Earth exerts a gravitational force on the ball, but the ball exerts a gravitational force of the same magnitude (and in the opposite direction) on the Earth.
Explanation:
Formula depicting relation between total flux and total charge Q is as follows.
(Gauss's Law)
Putting the given values into the above formula as follows.
Q = 
= 
= 
= -8.4 nC
Therefore, when the unknown charge is q then,
-14.0 nC + 33.0 nC + q = -8.4 nC
q = -27.4 nC
Thus, we can conclude that charge on the third object is -27.4 nC.
