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Agata [3.3K]
2 years ago
11

Write the examples of unit​

Physics
1 answer:
OLga [1]2 years ago
5 0

Answer:

The definition of a unit is a fixed standard amount or a single person, group, thing or number. An example of a unit is a single apartment in an apartment building

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Malcolm and Ravi raced each other. The average of their maximum speeds was 260 km/h If doubled, Malcolm's maximum speed would be
AfilCa [17]

Answer

Given,

Average speed of Malcolm and Ravi = 260 km/h

Let speed of the Malcolm be X and speed of the Ravi Y.

From the given statement

\dfrac{X+Y}{2}=260

X + Y = 520 ....(i)

2X - Y = 80  ....(ii)

Adding both the equations

3 X = 600

 X = 200 km/h

Putting value in equation (i)

Y = 520 - 200

Y = 320 Km/h

Speed of Malcolm = 200 Km/h

Speed of Ravi = 320 Km/h

8 0
3 years ago
Which examples are simple machines?
frozen [14]
A hammer and a pulley
4 0
2 years ago
9.
Ghella [55]

Given parameters:

Mass of the body  = 200g

Force on the body  = 10N

Unknown parameters:

Acceleration produced by the force  = ?

To solve this problem we must first define force in terms of mass and acceleration. This is possible due to the Newton's first law of motion.

  Force  = mass x acceleration

Here the unknown is acceleration and we can easily solve for it.

But we must take the mass to kilogram in order for it to cancel out.

        1000g  = 1 kg

        200g  = x kg =   \frac{200}{1000}   = 0.2kg

Now input the parameters and solve;

         10  = 0.2 x acceleration

   Acceleration  = \frac{10}{0.2}   = 50m/s²

The acceleration produced by the body is 50m/s²

4 0
3 years ago
What does the zeroth law of thermodynamics allow us to define?
REY [17]
The zeroth law of thermodynamics states that if two thermodynamic systems each are in thermal equilibrium with a third, then they are in thermal equilibrium with each other.
3 0
2 years ago
Read 2 more answers
The drawing shows four sheets of polarizing material, each with its transmission axis oriented differently. Light that is polari
Brrunno [24]

Answer:

Explanation:

When sheet A is removed

I_B=32\cos^230=24W/m^2\\\\I_C=24 \cos^260=6W/m^2\\\\I_D=6\cos^230=4.5W/m^2

When sheet B is removed

I_A=32\cos^20=32W/m^2\\\\I_C=24 \cos^290=0W/m^2\\\\I_D=0\cos^230=0W/m^2

When sheet C is removed

I_A=32\cos^20=32W/m^2\\\\I_D=32 \cos^230=24W/m^2\\\\I_B=24\cos^290=0W/m^2

When sheet D is removed

I_A=32\cos^20=32W/m^2\\\\I_B=32\cos^230=24W/m^2\\\\I_C=24\cos^260=6W/m^2

8 0
3 years ago
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