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kumpel [21]
4 years ago
14

Ask Your Teacher A coil is formed by winding 260 turns of insulated 16 gauge copper wire (diameter = 1.3 mm) in a single layer o

n a cylindrical form of radius 15 cm. What is the resistance of the coil? Neglect the thickness of the insulation.
Physics
1 answer:
Liula [17]4 years ago
4 0

Answer:

The resistance is 2.98Ω

Explanation:

<u>Data</u>

diameter:  d=1.3mm, d=1.3*10^{-3} m

Radius:    r=\frac{d}{2} ,r=\frac{1.3*10^{-3} }{2} ,r=6.5*10^{-4} m

Resistivity constant:   p=1.65*10^{-8}Ωm

To find Area:

A=\pi r^{2} \\A=\frac{22}{7} *(6.5*10^{-4} )\\A=1.33*10^{-6} m^{2}

To find circumference:

l=260*(2\pi (0.15))\\l=245.04m

Now we can apply the Resistivity formula:

R=p\frac{l}{A}

R=(1.65*10^{-8} )Ωm*\frac{240.04m}{1.33*10^{-6}m^{2}  }

R=2.98Ω

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