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Marysya12 [62]
3 years ago
13

Of the choices, which metal element would be the most reactive? (Please explain why the answer is the answer).

Chemistry
2 answers:
mart [117]3 years ago
7 0

Answer:

sulfur

Explanation:

sulfur because it have unknown metal

i just got done with the unit 2 weeks ago

sasho [114]3 years ago
5 0
A sulfur because it is the closest to fr
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How many grams are in 2 moles of Iodine?
Nady [450]

Answer: 253.8

Explanation:

The molar mass of iodine is 126.904. Multiply that by two and you get approximately 253.8 grams in two moles.

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2 years ago
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How many dots would the correct Lewis-Dot structure for carbon have? <br> 1 <br> 4 <br> 3 <br> 2
shutvik [7]

When creating a Lewis-Dot structure for Carbon, you'll want to put 4 "dots"

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3 years ago
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Consider 100.0-g samples of two different compounds consisting only of carbon and oxygen. one compound contains 27.2 g of carbon
Sliva [168]

This is a tricky question. All that matters are ratios of percentages, not percentages themselves. So no one should directly compare 27.2 with 42.9. We must and shall compare the ratios (27.2 to 72.8) and (42.9 to 57.1).

Take them both down to 1 to and see what happens.

Working out the formulas knowing atomic masses is a bit beside the point; this is how people first DISCOVERED the idea of atomic mass.

A

Carbon Oxygen

27.2g 72.8g (100-27.2)

Moles 27.2/12 72.8/16

2.27 4.55

Ratio 1 2

Do the same with the other

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3 years ago
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Baking soda (NaHCO3) and vinegar (HC2H3O2) react to form sodium acetate, water, and carbon dioxide. If 42.00 g of baking soda re
Setler [38]

Answer:

0.5 mole of CO₂.

Explanation:

We'll begin by calculating the number of mole in 42 g of baking soda (NaHCO₃). This can be obtained as follow:

Mass of NaHCO₃ = 42 g

Molar mass of NaHCO₃ = 23 + 1 + 12 + (16×3)

= 23 + 1 + 12 + 48

= 84 g/mol

Mole of NaHCO₃ =?

Mole = mass / molar mass

Mole of NaHCO₃ = 42/84

Mole of NaHCO₃ = 0.5 mole

Next, balanced equation for the reaction. This is given below:

NaHCO₃ + HC₂H₃O₂ → NaC₂H₃O₂ + H₂O + CO₂

From the balanced equation above,

1 mole of NaHCO₃ reacted to produce 1 mole of CO₂

Finally, we shall determine the number of mole of CO₂ produced by the reaction of 42 g (i.e 0.5 mole) of NaHCO₃. This can be obtained as follow:

From the balanced equation above,

1 mole of NaHCO₃ reacted to produce 1 mole of CO₂.

Therefore, 0.5 mole of NaHCO₃ will also react to produce 0.5 mole of CO₂.

Thus, 0.5 mole of CO₂ was obtained from the reaction.

7 0
2 years ago
A 93-L sample of dry air is cooled from 145 oC to -22 oC at a constant pressure of 2.85 atmospheres). What is the final volume?
Aloiza [94]

Answer: 55.84L

Explanation: Please see attachment for explanation.

3 0
3 years ago
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