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Galina-37 [17]
3 years ago
8

G- how many grams of f2 gas are there in a 5.00-l cylinder at 4.00 × 103 mm hg and 23°c?

Chemistry
1 answer:
aniked [119]3 years ago
6 0
<span>PV = nRT (4000 Torr)(5 L) = n (62.4 Torr-L/mol-K)(296K) n = 1.08 moles 28 g/mol, 1.08 moles = 30.3 grams your answer is C.30.3 g</span>
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Answer: There are now 2.07 moles of gas in the flask.

Explanation:

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V=\frac{nRT}{P}=\frac{1.9\times 0.0821 \times 294}{0.92}=49.8L

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PV=nRT

P= Pressure of the gas = 775 mmHg = 1.02 atm  (760 mmHg= 1 atm)

V= Volume of gas = volume of container = 49.8 L

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T = Temperature of the gas = 26°C=(26+273)K= 299 K   (0°C = 273 K)

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n=\frac{PV}{RT}=\frac{1.02\times 49.8}{0.0821\times 299}=2.07moles

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