Answer:
C.
Explanation:
![\frac{1x10}x^{-14} = 1x10^{-9} \\ x =1x10^{-5} \\\\[OH][H]= 1x10^{-14}](https://tex.z-dn.net/?f=%5Cfrac%7B1x10%7Dx%5E%7B-14%7D%20%3D%201x10%5E%7B-9%7D%20%5C%5C%20x%20%3D1x10%5E%7B-5%7D%20%5C%5C%5C%5C%5BOH%5D%5BH%5D%3D%201x10%5E%7B-14%7D)
The concetration can be found by dividing the water ph constant by the [H=] or [OH] to find the other
Answer:
1.55
Explanation:
-log(M)=pH
- Hope that helps! Please let me know if you need further explanation.
Hello, here’s the answer to your question. Converting ammonia to nitrate, which is absorbed by plants
Answer: The concentrations of
at equilibrium is 0.023 M
Explanation:
Moles of
= 
Volume of solution = 1 L
Initial concentration of
= 
The given balanced equilibrium reaction is,

Initial conc. 0.14 M 0 M 0M
At eqm. conc. (0.14-x) M (x) M (x) M
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[CO]\times [Cl_2]}{[COCl_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCO%5D%5Ctimes%20%5BCl_2%5D%7D%7B%5BCOCl_2%5D%7D)
Now put all the given values in this expression, we get :

By solving the term 'x', we get :
x = 0.023 M
Thus, the concentrations of
at equilibrium is 0.023 M