G- how many grams of f2 gas are there in a 5.00-l cylinder at 4.00 × 103 mm hg and 23°c?

1 answer:

6 0

PV = nRT (4000 Torr)(5 L) = n (62.4 Torr-L/mol-K)(296K) n = 1.08 moles 28 g/mol, 1.08 moles = 30.3 grams your answer is C.30.3 g

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