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notsponge [240]
3 years ago
11

A gas occupies a volume of 30.0L, a temperature of 25°C and a pressure of 0.600atm. What will be the volume of the gas at STP?​

Chemistry
1 answer:
Shalnov [3]3 years ago
5 0

Answer:

=16.49 L

Explanation:

Using the equation

P1= 0.6atm V1= 30L, T1= 25+273= 298K, P2= 1atm, V2=? T2= 273

P1V1/T1= P2V2/T2

0.6×30/298= 1×V2/273

V2=16.49L

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CaC2 + 2H2O ⟶ C2H2 + Ca(OH)2<br><br> How many moles of water are needed to produce 56.8g C2H2?
pshichka [43]

Amount of moles of water is 4.36 mol

Explanation: M(C2H2) = 2·12.01 + 2·1.008 = 26.036 g/mol

Amount of substance is n= m/M= 56.8 g / 26.036 g/mol= 2.18159 mol

Water is needed 2·2.18 mol = 4.36 mol

6 0
3 years ago
Balance the equation above please ​
Anon25 [30]

Answer:

<h3><em><u>Balanced</u></em><em><u> </u></em><em><u>Equation</u></em><em><u>:</u></em><em><u>-</u></em></h3>

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6 0
3 years ago
Read 2 more answers
A particle accelerates from rest with an acceleration of 8.0m/s2. Calculate its velocity after 150s. What kinematic formula must
Ipatiy [6.2K]

<u>Answer</u>:

Final velocity: 1200 m/s

<u>Explanation</u>:

Formula:   \overline{a} = \frac{v - v_0}{t} = \frac{\Delta v}{\Delta t}

<u>Where</u>:

a = average acceleration

v = final velocity

vo = starting velocity

t = elapsed time

<em>Here the final velocity is unknown which we have to find. The initial is 0 m/s</em>

<em>as it was at rest. The time taken: 150 seconds. Acceleration given 8.0 m/s²</em>

using the formula:

\overline{a} = \frac{v - v_0}{t}

8 = \frac{v - 0}{150}

v = 1200 m/s

4 0
3 years ago
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aivan3 [116]
Table salt is a compound because Sodium (Na) and Chlorine (Cl) were combined to make a new group.
3 0
3 years ago
How many grams of carbon monoxide are needed to react with an excess of iron (III) oxide to produce 198.5 grams of iron? Fe2O3(s
erastova [34]

Answer : The grams of carbon monoxide needed are 148.89 g

Solution : Given,

Mass of iron, Fe = 198.5 g

Molar mass of iron, Fe = 56 g/mole

Molar mass of carbon monoxide, CO = 28 g/mole

First we have to calculate the moles of iron, Fe.

\text{ Moles of Fe}=\frac{\text{ Mass of Fe}}{\text{ Molar mass of Fe}}=\frac{198.5g}{56g/mole}=3.545moles

The balanced chemical reaction is,

Fe_2O_3(s)+3CO(g)\rightarrow 3CO_2(g)+2Fe(s)

From the balanced reaction, we conclude that

2 moles of iron produces from the 3 moles of carbon monoxide

3.545 moles of iron produces from the \frac{3}{2}\times 3.545=5.3175 moles of carbon monoxide

Now we have to calculate the mass of carbon monoxide, CO.

\text{ Mass of CO}=\text{ Moles of CO}\times \text{ Molar mass of CO}

\text{ Mass of CO}=(5.3175moles)\times (28g/mole)=148.89g

Therefore, the grams of carbon monoxide needed are 148.89 g

7 0
3 years ago
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