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LuckyWell [14K]
3 years ago
9

Suppose you flip 3 quarters, one at a time. What is the probability that you will

Mathematics
1 answer:
Semenov [28]3 years ago
7 0

Answer:

The probability of the combination {H, T and H} is 0.125.

Step-by-step explanation:

The sample space of flipping a quarter is:

S = {H and T}

The probability of both outcomes is same, i.e. P (H) = P (T) = 0.50.

It is provided that three quarters are flipped one at a time.

The outcomes of all the three quarters are independent of each other.

Compute the probability of the combination {H, T and H} as follows:

P(\text{H},\text{T and H}) = P(\text{H})\times P(\text{T})\times P(\text{H})

                        =0.50\times 0.50\times 0.50\\=0.125

Thus, the probability of the combination {H, T and H} is 0.125.

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• rewrite tan = sin/cos

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• expand the functions of 2<em>A</em> using the double angle identities

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• rearrange terms in the product

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• divide through again by cos²(<em>A</em>)

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• rewrite sin/cos = tan and 1/cos = sec

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• factor out sec²(<em>A</em>) in the denominator

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• rewrite using the Pythagorean identity, sec²(<em>A</em>) = 1 + tan²(<em>A</em>)

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• simplify

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• condense the denominator as the difference of squares

… = 4 tan(<em>A</em>) / (1 - tan⁴(<em>A</em>))

(Note that some of these steps are optional or can be done simultaneously)

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