Answer:
on what's app ?
Step-by-step explanation:
or telegram ?
Answer: X = 10.20240940...
Step-by-step explanation:
x(2x + 9) = 2x^2 + 9x
2x^2 + 9x = 300
- 300 ON BOTH SIDES
2x^2 + 9x - 300 = 0
SOLVE USING THE QUADRATIC FORMULA
x = -b +/- all root (b)^2 - 4(a)(c) All over 2(a)
When all the values are plugged in:
When using "+" in the equation you should get:
x = 10.20240940…
When using "-" in the equation you should get:
x = −14.70240940…
Now.. you CANNOT have a negative length, so you cross of the negative value leaving you one value for x which is 10.20240940...
YOUR ANSWER IS: x = 10.20240940...
Answer:
a) Median stays the same
b) Mean is decreased by $9
Step-by-step explanation:
The median is the number or the average of the two numbers that is in the middle of a sorted distribution of numbers,
Here the median number will be the 5th number counting from left or right from the sorted list of numbers. Therefor is is 891.
When 1027 is changed to 946 it will fall between 938 and 1002. So updated sorted list of numbers will now look like,
679, 715, 799, 844, 891, 917, 938, 946, 1002
Here also median will be the 5th number which will be equal to 891.
Therefore, , median will not change.
Mean is the value we get by taking the total value of the salaries and divide it by the number of employees.
In the initial case,
Mean =
When the salary is changed from $1027 to $946,
Mean=
Therefor we can see that Mean has decreased by $9.
Answer:
-44
Step-by-step explanation:
<em>Complete Question:</em>
<em>You plant an 8-inch spruce tree that grows 4 inches per year and a 14-inch hemlock tree that grows 6 inches per year. </em>
<em>The initial heights are shown. </em>
Write a system of linear equations that represents this situation.
Answer:


Step-by-step explanation:
Given
Spruce Tree (s):

(yearly)
Hemlock Tree (h):

(yearly)
Required
Represent as system of linear equations
Let the number of years be x.
In both cases, the equation can be formed using:

For Spruce Tree (s):


For Hemlock Tree (h):


<em>Hence, the equations are </em>
<em> and </em>
<em></em>