Answer:
264,600J
Explanation:
Gpe = mgh, knowing that the acceleration due to gravity,g, is 9.8N/kg.
<span>THIS IS A GAS PHASE REACTION AND WE ARE GIVE PARTIAL PRESSURES . I WRITE IN TERMS OF P RATHER THAN CONCENTRATION :
lnPso2cl12=-kt+lnPso2cl1
initial partial pressure Pso2cl12 the rate constant k and the time t
lnPso2cl12=(4.5*10-2*s-1)*65*s+ln (375)
so lnPso2cl12=3.002
we take the base e antilog:
lnPso2cl12=e3.002
Pso2cl12=20 torr
we use the integrated first order rate
lnPso2cl12=3.002=k*t+ lnPso2cl12=3.002
we use the same rate constant and initial pressure
k=4.5*10-2*s-1
Pso2cl12=375
Pso2cl12=1* so2cl12
Pso2cl12=37.5 torr
subtract in Pso2cl12 grom both side
lnPso2cl12- lnPso2cl12=-kt
ln(x)-ln(y)=ln (x/y)
ln (Pso2cl12/Pso2cl20)=-kt
we get t
-1/k*ln(Pso2cl12/Pso2cl20)=t
t=51 s</span>
Answer:
Number 6:
• From the formula of force:
• But we need to get the acceleration, from the first newtons equation of motion
• v is the final velocity, but v is zero because the bullet came to rest.
• u is the initial velocity, u = 350 m/s
• a is the acceleration that we need
• t is the time, t = 0.0018 seconds.
» let's now substitute:
[ negative shows retârdation or deceleration or decrease in speed ]
• Therefore, let's find the force:
mass = 6g = (6/1000) kg = 0.006 kg
Answer:
the sun or Me not sure but one of them has to be ...