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frozen [14]
3 years ago
8

You can send your pictureand type the answer to the questions

Physics
1 answer:
Snowcat [4.5K]3 years ago
3 0
The answer is B because I took the test and had the question
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A student mixes two substances in a large beaker. After two hours, the student sees that the substances have separated again.
S_A_V [24]

The full question is found in the image attached

Answer:

Densities

Explanation:

When we talk about density, one of the things that come to our mind is actually how heavy something is.

If i have substances that possess different densities, i will notice that i can not really mix them because they will separate and the heavier substance will be at the bottom while the lighter substance will be at the top.

Hence the two substances separated due to difference in density.

7 0
2 years ago
9. A sailor pulls a boat along a dock using a rope at an angle of 60.0° with the
aleksklad [387]

Answer: (1) 3.83x10^3 J

Explanation:

(1) Fx=(255N)cos60°

   dx=30.0m

   w=Fx dx =(255)(cos60°)(30.0m)

6 0
3 years ago
If themass is 50kg, what weight of water is to be displaced to float on water? why
ludmilkaskok [199]

Answer:if youre looking for the weight of the thermas in genral it should be 500n

Explanation:using the formula w=mg

w=500x10

giving us 500 newtons which is the weight.

5 0
1 year ago
Zorn and Porsha are ice skating. Porsha has a mass of 60 kg, and Zorn has a mass of 40 kg. As they face each
algol13

Assuming the friction between the skaters and the ice is  negligible, the magnitude of Porsha's acceleration is 2.8m/s².

Missing part of the question: determine the magnitude of Porsha's acceleration.

Given the data in the question;

  • Mass of Porsha; m_{porsha} = 60kg
  • Mass of Zorn; m_{zorn} = 40kg
  • Force of Porsha push; F_{porsha} = 168N

Magnitude of Porsha's acceleration; a = \ ?

To determine the magnitude of Porsha's acceleration, we use Newton's second laws of motion:

F = m*a

Where m is the mass of the object and a is the acceleration.

We substitute the mass of Porsha and the force he used into the equation

168N = 60kg * a\\\\a = \frac{168kg.m/s^2}{60kg}\\\\a = 2.8m/s^2

Therefore, assuming the friction between the skaters and the ice is  negligible, the magnitude of Porsha's acceleration is 2.8m/s².

Learn more: brainly.com/question/25125444

3 0
3 years ago
How can i prove the conservation of mechanical energy?​
FinnZ [79.3K]

Answer:

We can also prove the conservation of mechanical energy of a freely falling body by the work-energy theorem, which states that change in kinetic energy of a body is equal to work done on it. i.e. W=ΔK. And ΔE=ΔK+ΔU. Hence the mechanical energy of the body is conserved

Explanation:

5 0
2 years ago
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