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What is Newton's third law ?

tatyana61 [14]

Answer:

every action has an equal and opposite reaction

plz mark me brainliest

3 0

3 years ago

Read 2 more answers

A candy-filled piñata is hung from a tree for Elia's birthday. During an unsuccessful attempt to break the 4.4-kg piñata, Tonja

Klio2033 [76]

Answer: v = 0.6 m/s

Explanation: Momentum Conservation Principle states that for a collision between two objects in an isolated system, the total momentum of the objects before the collision is equal to the total momentum of the objects after the collision.

Momentum is calculated as Q = m.v

For the piñata problem:

$Q_{i}=Q_{f}$

$m_{p}v_{p}_{i}+m_{s}v_{s}_{i}=m_{p}v_{p}_{f}+m_{s}v_{s}_{f}$

Before the collision, the piñata is not moving, so $v_{p}_{i}=0$ .

After the collision, the stick stops, so $v_{s}_{f}=0$ .

Rearraging, we have:

$m_{s}v_{s}_{i}=m_{p}v_{p}_{f}$

$v_{p}_{f}=\frac{m_{s}v_{s}_{i}}{m_{p}}$

Substituting:

$v_{p}_{f}=\frac{(0.54)(4.8)}{(4.4)}$

$v_{p}_{f}=$ 0.6

Immediately after being cracked by the stick, the piñata has a swing speed of 0.6 m/s.

3 0

3 years ago

to 10 Hz. Superimposed on this signal is 60-Hz noise with an amplitude of 0.1 V. It is desired to attenuate the 60-Hz signal to

givi [52]

Answer:

$G \sqrt{1 +(\frac{f}{f_c})^{2n}} = 1$

If we square both sides we got:

$G^2 (1+\frac{f}{f_c})^{2n}= 1$

We divide both sides by $G^2$ and we got:

$(1+\frac{f}{f_c})^{2n} = \frac{1}{G^2}$

Now we can apply log on both sides and we got:

$2n ln(1+\frac{f}{f_c}) = ln (\frac{1}{G^2})$

And solving for n we got:

$n = \frac{ ln (\frac{1}{G^2})}{2ln(1+\frac{f}{f_c})}$

And replacing we got:

$n = \frac{ln (\frac{1}{0.1^2})}{2ln(1+\frac{60}{10})}$

$n = \frac{4.60517}{3.8918}=1.18$

And since n needs to be an integer the correct answer would be n=2 for the filter order.

Explanation:

For this case we can use the formula for the Butterworth filter gain given by:

[tec] G = \frac{1}{\sqrt{1 +(\frac{f}{f_c})^{2n}}}[/tex]

Where:

G represent the transfer function and we want that G =0.1 since the desired signal is less than 10% of it's value

$f_c = 10 Hz$ represent the corner frequency

$f= 60 Hz$ represent the original frequency

n represent the filter order and that's the variable that we need to find

$G \sqrt{1 +(\frac{f}{f_c})^{2n}} = 1$

If we square both sides we got:

$G^2 (1+\frac{f}{f_c})^{2n}= 1$

We divide both sides by $G^2$ and we got:

$(1+\frac{f}{f_c})^{2n} = \frac{1}{G^2}$

Now we can apply log on both sides and we got:

$2n ln(1+\frac{f}{f_c}) = ln (\frac{1}{G^2})$

And solving for n we got:

$n = \frac{ ln (\frac{1}{G^2})}{2ln(1+\frac{f}{f_c})}$

And replacing we got:

$n = \frac{ln (\frac{1}{0.1^2})}{2ln(1+\frac{60}{10})}$

$n = \frac{4.60517}{3.8918}=1.18$

And since n needs to be an integer the correct answer would be n=2 for the filter order.

7 0

3 years ago

Choose all the answers that apply. Which of the following occurs during data analysis? observations are made statistical informa

denis23 [38]

Answer:

Both of them.

Explanation:

They are both because when your analyzing data , that is what happen's.

6 0

3 years ago

A car tire rotates with an average angular speed of 29 rad/s. In what time interval will the tire rotate 3.5 times?

meriva

Answer:

"0.758315 sec" is the appropriate choice.

Explanation:

The given values are:

Angular speed,

= 29 rad/s

or,

= $\frac{29}{2 \pi} \ rps$

Tire rotates,

= 3.5 times

Now,

The time interval will be:

⇒ $\Delta t=\frac{3.5}{\frac{29}{2 \pi} }$

⇒ $=\frac{2 \pi\times 3.5}{29}$

⇒ $=\frac{21.99}{29}$

⇒ $=0.758315 \ sec$

8 0

3 years ago

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