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Katena32 [7]
2 years ago
6

What sort of process converts the mechanized energy in the ocean into electricity?

Physics
1 answer:
allochka39001 [22]2 years ago
5 0
I think it is the wave energy. 
Wave energy also known as the ocean energy is the energy harnessed from the ocean or sea waves. It is a source of power that comes from the endless march of the waves as they roll into the shore then back out. Using wave energy is advantageous as they are environmental friendly as there are no harmful byproducts, and also the energy from waves can be taken directly into electricity-producing machinery and used to power generators. 
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A student places his hand in front of a plane mirror as shown in the diagram. Which terms correctly describe the image that the
ANTONII [103]
Either A or D but maybe D
4 0
2 years ago
What is the numerical value of the slope of the line (without units)?<br>0.083<br>24<br>8.3<br>12
tankabanditka [31]
As close as I can read it, it appears to be

                 1/12  gram/second

           (0.08333... gm/sec)
4 0
3 years ago
A certain field line diagram illustrates the electric field due to three particles that carry charges 5.0 μC, -3.0 μC, and -2.0
4vir4ik [10]

Answer:

6

Explanation:

Number of lines emanate from + 5 micro coulomb is 15 .

They terminates at negative charges that means at - 3 micro coulomb and - 2 micro Coulomb.

the electric field lines terminates at - 3 micro Coulomb and - 2 micro Coulomb is in the ratio of 3 : 2.

So the lines terminating at - 3 micro coulomb

                                    = \frac{3}{5}\times 15 = 9

So the lines terminating at - 2 micro coulomb

                                    = \frac{2}{5}\times 15 = 6

So, the number of filed lines terminates at - 2 micro Coulomb are 6.

4 0
3 years ago
object P1 and P2 are in a straight line with the normal to a plane mirror.If P1 and P2 are 18m and 21m away from the mirror. Cal
VARVARA [1.3K]

The distance between object P1 and its image formed is determined as 36 m.

<h3>Distance of the image</h3>

The distance of the image formed by object P1 is calculated as follows;

In a plane mirror; object distance = image distance

image distance of P1 = 18 m

distance between object and image = 18m + 18 m = 36 m

Thus, the distance between object P1 and its image formed is determined as 36 m.

Learn more about plane mirrors here: brainly.com/question/1126858

#SPJ1

8 0
1 year ago
A thermometer initially reading 212F is placed in a room where the temperature is 70F. After 2 minutes the thermometer reads 125
frez [133]

Answer:

91.3°F

Explanation:

Let T be the temperature of the thermometer at any time

T∞ be the temperature of the room = 70°F

T₀ be the initial temperature of the thermometer = 212°F

And m, c, h are all constants from the cooling law relation

From Newton's law of cooling

Rate of Heat loss by the cake = Rate of Heat gain by the environment

- mc (d/dt)(T - T∞) = h (T - T∞)

(d/dt) (T - T∞) = dT/dt (Because T∞ is a constant)

dT/dt = (-h/mc) (T - T∞)

Let (h/mc) be k

dT/(T - T∞) = -kdt

Integrating the left hand side from T₀ to T and the right hand side from 0 to t

In [(T - T∞)/(T₀ - T∞)] = -kt

(T - T∞)/(T₀ - T∞) = e⁻ᵏᵗ

(T - T∞) = (T₀ - T∞)e⁻ᵏᵗ

Inserting the known variables

(T - 70) = (212 - 70)e⁻ᵏᵗ

(T - 70) = 142 e⁻ᵏᵗ

At t = 2 minute, T = 125°F

125 - 70 = 142 e⁻ᵏᵗ

55/142 = e⁻ᵏᵗ

- kt = In (55/142) = In (0.3873)

- k(2) = - 0.9485

k = 0.4742 /min

At time t = 4 mins

kt = 0.4742 × 4 = 1.897

(T - 70) = 142 e⁻ᵏᵗ

e^(-1.897) = 0.15

T - 70 = 142 × 0.15 = 21.3

T = 91.3°F

7 0
3 years ago
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