Answer:
b.materials input quantity
Explanation:
A cost of production report shows the following:
- total and unit costs transferred from preceding department
- materials, labor , factory Overhead added by the department
- unit costs added by the department
- total and unit costs accumulated to the end of operations
- the cost of beginning and ending work in process inventories
- the cost transferred to the next department
A cost of production report determines periodic total and unit costs.
Either in the cost of production report or in the supporting schedule each item of material used is listed, every labor operation is shown separately,factory overhead components are noted individually, and a unit cost is derived for each item.
A Quantity Schedule Of Cost of Production report shows the following
- units started in process
- units transferred to next department
- units still in process
- units lost in process
Specific heat of Aluminium is 0.89 g/J
Explanation:
Step 1 :
Specific heat of a substance is the energy absorbed by a substance of unit mass when its temperature increases by one degree.
Energy Absorbed = Specific Heat * Mass of the substance * Temperature Difference
Step 2 :
It is given that 120 g sample absorbs 9612 J energy when the temperature increases from 298K to 388K.
Temperature Difference = 388 K - 298 K = 90 K
Step 3:
Specific Heat = (Energy Absorbed) ÷ (Mass of the substance * Temperature Difference)
Specific Heat = 9612 ÷ (120 * 90) = 0.89 grams / Joule
Step 4:
Answer:
Specific heat of Aluminium is 0.89 g/J
To
determine the empirical formula of the compound given, we need to determine the ratio of each element in the compound. To do that we assume to have 100 grams sample
of the compound with the given composition. Then, we calculate for the number
of moles of each element. We do as follows:<span>
mass moles
C 56.79 4.73
H 6.56 6.50
O 28.37 1.77
N 8.28 0.59
Dividing the number of moles of each element with
the smallest value, we will have the empirical formula:
</span> moles ratio
C 4.73 / 0.59 8
H 6.50 / 0.59 11
O 1.77 / 0.59 3
N 0.59 / 0.59 1<span>
</span><span>
The empirical formula would be C8H11O3N.</span>
Answer:
0.670 mol
Explanation:
Step 1: Write the balanced reaction for the decomposition of alumina
2 Al₂O₃ ⇒ 4 Al + 3 O₂
Step 2: Calculate the moles corresponding to 34.2 g of Al₂O₃
The molar mass of Al₂O₃ is 101.96 g/mol.
34.2 g × 1 mol/101.96 g = 0.335 mol
Step 3: Calculate the moles of Al produced from 0.335 moles of Al₂O₃
The molar ratio of Al₂O₃ to Al is 2:4.
0.335 mol Al₂O₃ × (4 mol Al/2 mol Al₂O₃) = 0.670 mol Al
Answer:
H2 < CH3Cl < HF
Explanation:
The intermolecular forces are the forces that bond the molecules together in a substance. There are three types of these forces:
- Dipole induced -dipole induced, or London dispersion -> Is the weakest and is presented in nonpolar molecules, in which a dipole is induced and so the molecules are joined together;
- Dipole-dipole -> Is stronger than the London dispersion and occurs in a polar molecule. In this case, the dipole already exists (partial positive and negative charges), so the poles are attracted;
- Hydrogen bond -> It's the strongest and is formed when the hydrogen is bonded with a higher electronegativity element (F, O, and N).
So, the molecule of H2 is linear and formed by the same element, so, is nonpolar, and has London dispersion forces. The molecule of CH3Cl has 3 nonpolar bonds (C-H), and one polar bond (C-Cl), so it's polar and has dipole-dipole forces. And the HF molecule has hydrogen bonds.
*A polar bond is a bond formed by elements with different electronegativities.
