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Ivan
3 years ago
10

True or False: Marijuana/Cannabis causes physical dependence

Chemistry
1 answer:
makkiz [27]3 years ago
4 0

Answer:

False

Explanation:

It is psychological for you do not depend on it to live.

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Which type of energy is stored in the nucleus of an atom?
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Nuclear energy is energy in the nucleus (core) of an atom. Atoms are tiny particles that make up every object in the universe. There is enormous energy in the bonds that hold atoms together. Nuclear energy can be used to make electricity.
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3 years ago
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Help me with this this is something i dont know and its not on here please help meeeeeee
denis-greek [22]

Answer:

it would be option A

Explanation:

This is becuase if you look at the chart you can see tyhat the group of rats that got feed to vitamans did gain more wati then the ones on the normal diet.

8 0
2 years ago
Calculate the mass of chromium metal produced when 425.0mL of 0.25M chromium(ll) nitrate reacts with a strip of zinc that remain
Reil [10]

The balanced chemical equation for the production of chromium metal from the reaction of chromium(ll) nitrate reacts with a strip of zinc is:

3 Zn + 2 Cr(NO₃)₃ → 2 Cr + 3 Zn(NO₃)₂

This is a redox reaction, which <u>is a chemical reaction in which one or more electrons are transferred between the reagents</u>, causing a change in their oxidation states. In the proposed reaction, Cr oxidation state goes from +3 to 0, becoming metallic chromium, while Zn goes from being Zn⁰ to Zn²⁺.

<u>The mass of chromium metal produced in the above reaction will be,</u>

425.0 mL x \frac{1 L}{1000 mL} x  \frac{0.25 mol Cr(NO_{3})_{3}  }{1 L} x \frac{2 mol Cr  }{2 mol Cr(NO_{3})_{3} } x \frac{51.9961 g Cr}{1 mol Cr} = 5.52 g

So, the mass of chromium metal produced when 425.0mL of 0.25M chromium(ll) nitrate reacts with a strip of zinc that remains in excess is 5.52 g of Cr.

6 0
3 years ago
What is the effect of the following on the volume of 1 mol of an ideal gas? The temperature changes from 305 K to 32°C and the p
ryzh [129]

Answer:

The volume increases by 100%.

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<u>Step 1:</u> Data given

Number of moles ideal gas = 1 mol

Initial temperature = 305 K

Final temperature = 32°C + 273.15 = 305.15 K

Initial pressure = 2 atm

final pressure = 101 kPa = 0.996792 atm

R = gasconstant = doesn't change

V1 = initial volume

V2= the final volume

<u>Step 2: </u>Calculate volume of original gas

P*V = n*R*T

(P*V)/ T = constante

(P1 * V1) / T1 = (P2 * V2)/ T2

In this situation we have:

(2atm * V1)/ 305  = (0.996792 *V2) / 305.15

0.006557*V1 = 0.003266*V2

V2 = 2*V1

We see that the final volume is twice the initial volume. So the volume gets doubled. The volume increases by 100%.

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