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marin [14]
3 years ago
5

What orbitals are used to form the 10 sigma bonds in propane (ch3ch2ch3)? Label each atom with the appropriate hybridization. Dr

ag the appropriate labels to their respective targets. Note: not all labels will be used?

Chemistry
1 answer:
SVETLANKA909090 [29]3 years ago
3 0

Mixing of pure orbitals having nearly equal energy to form equal number of completely new orbitals is said to be hybridization.

For the compound, CH_3CH_2CH_3 the electronic configuration of the atoms, carbon and hydrogen are:

Carbon (atomic number=6): In ground state= 1s^{2}2s^{2}2p^{2}

In excited state: 1s^{2}2s^{1}2p^{3}

Hydrogen (atomic number=1): 1s^{1}

All the bonds in the compound is single bond(\sigma-bond) that is they are formed by head on collision of the orbitals.

The structure of the compound is shown in the image.

The Carbon-Hydrogen bond is formed by overlapping of s-orbital of hydrogen to p-orbital of carbon.

In order to complete the octet the required number of electrons for carbon is 4 and for hydrogen is 1. So, the electron in 1s^{1} of hydrogen will overlap to the 2p^{3}-orbital of carbon.

Thus, the hybridization of Hydrogen is s-hybridization and the hybridization of Carbon is sp^{3}-hybridization.

The hybridization of each atom is shown in the image.

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Answer:

1. B

2. C

3. B or D

6. A

7. D

8. A

9. A

Explanation:

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6 0
3 years ago
3. The sum of gravitational potential energy and kinetic energy is called mechanical
SCORPION-xisa [38]

Answer:

Explanation:

Mechanical energy = Kinetic energy + Potential energy

We shall calculate mechanical energy at different points of time .

Time        Kinetic energy         Potential energy      mechanical energy

   0                     0                                 4                                  4

    2                     2                                  2                                 4

     4                    4                                  0                                  4

      6                   2                                  2                                  4

     8                    0                                   4                                  4

     10                    2                                   2                                 4

and so on ........

Hence we see that total mechanical energy is constant at the value of 4

at all time .

4 0
3 years ago
1. If you have 8.1 g CO₂ and 2.3 g H₂, which one is the limiting reactant. Show your work. 2. Calculate the theoretical yield of
ZanzabumX [31]

Answer:

2.95 g of CH₄

Explanation:

To start this, we determine the equation:

4H₂  + CO₂ →  CH₄  +  2H₂O

4 moles of hydrogen react to 1 mol of carbon dioxide in order to produce 1 mol of methane and 2 moles of water.

To determine the limiting reactant, we need to know the moles of each reactant.

8.1 g . 1 mol/ 44g = 0.184 moles of carbon dioxide

2.3 g . 1mol / 2g = 1.15 moles of hydrogen

4 moles of hydrogen react to 1 mol of CO₂

Then, 1.15 moles may react to (1.15 . 1) /4 = 0.2875 moles

We only have 0.184 moles of CO₂, so this is the limiting reactant. Not enough CO₂ to complete the 0.2875 moles that are needed.

Ratio is 1:1. 1 mol of CO₂ produces 1 mol of methane

Then, 0.184 moles of CO₂ will produce 0.184 moles of CH₄

We convert moles to mass: 0.184 mol . 16 g /mol = 2.95 g

7 0
3 years ago
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