The formula for a chemical reaction is given. 2Na + 2H2O → 2NaOH + H2 Which of the following describes this reaction? Group of a
1 answer:
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<u>Answer:</u> The total volume of the gaseous products is 1044.29 L
<u>Explanation:</u>
We are given:
Volume of butane = 116 L
At STP:
22.4 L of volume is occupied by 1 mole of a gas
So, 116 L of volume will be occupied by = of butane
The chemical equation for the combustion of butane follows:
- <u>For carbon dioxide:</u>
By Stoichiometry of the reaction:
2 moles of butane produces 8 moles of carbon dioxide
So, 5.18 moles of butane will produce = of carbon dioxide
Volume of carbon dioxide at STP = (20.72 × 22.4) = 464.13 L
- <u>For water vapor:</u>
By Stoichiometry of the reaction:
2 moles of butane produces 10 moles of water vapor
So, 5.18 moles of butane will produce = of water vapor
Volume of water vapor at STP = (25.9 × 22.4) = 580.16 L
Total volume of the gaseous products = [464.13 + 580.16] = 1044.29 L
Hence, the total volume of the gaseous products is 1044.29 L
Answer:
RbOH
Explanation:
For this question, we have to remember what is the definition of a base. A base is a compound that has the <u>ability to produce hydroxyl ions</u> , so:
With this in mind we can write the <u>reaction for each substance:</u>
The only compound that fits with the definition is , so this is our <u>base</u>.
I hope it helps!