Answer:
<h2><em><u>
.1etc</u></em></h2>
Step-by-step explanation:
It would be 16 divided by 3 and from the answer you get from that you should divide it by itself equaling infinite .111111111111etc
=Y2-10Y
We move all terms to the left:
-(Y2-10Y)=0
We add all the numbers together, and all the variables
-(+Y^2-10Y)=0
We get rid of parentheses
-Y^2+10Y=0
We add all the numbers together, and all the variables
-1Y^2+10Y=0
a = -1; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-1)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
Y1=−b−Δ√2aY2=−b+Δ√2a
Δ‾‾√=100‾‾‾‾√=10
Y1=−b−Δ√2a=−(10)−102∗−1=−20−2=+10
Y2=−b+Δ√2a=−(10)+102∗−1=0−2=0
Answer:
D because if you add 10 to negative ten the cancel out and make 0
Step-by-step explanation:
Wouldnt you need it to equal something? like a-5=b so then b+5=a
