V₀=6.35*4=25.4 m/s the speed of the when car enters into main speedway
S=V₂t
S=73t - distance of the second car
S=V₀t+at²/2
S=25.4t+6.35t²/2 - distance of the first car
6.35t²/2+25.4t=73t
t*(3.175t-47.6)
3.175t=47.6
t=14.99 s
14.99 s is required for the first car to catch the second
Answer:
E = 3544.44 N/C
Explanation:
Given:
- charge Q = 2.2 *10^-6 C
- Length L = 1.3 m
Find:
The Electric Field strength E @ a = 1.8 m
Solution:
- The differential electric field dE due to infinitesimal charge dq can be considered as a point charge at a distance of r is given by:
dE = k*dq / r^2
- The charge Q is spread over entire length L, hence:
dq = (Q / L ) * dx
-The resulting dE:
dE = (k*Q/L)*(dx / r^2)
- point P lies on the x- axis with distance (x+a) from differential charge from:
dE = (k*Q/L)*(dx / (x+a)^2)
- Integrate dE over length 0 to L
E = (-k*Q/L)*( 1 / (x+a) )
E = (-k*Q/L)* (1 / a - 1 / (L+a))
E = (-k*Q/L)* (L / a(L+a))
E = (k*Q / a(L+a))
- Evaluate E @ a = 1.8 m
E =(8.99*10^9 * 2.2*10^-6 / 1.8*(1.3+1.8))
E = 3544.44 N/C
First thermal energy (heat) is not the same thing as temperature. Thermal energy is internal energy held by the molecules but the temperature is the is the effect of the heat. Temperature is the measurement of the heat energy. Also, thermal energy depends on the size of the matter but the temperature isn't, it's just the average heat energy held by the matter.
Answer:
12.267 seconds approximately.
Explanation:
The units can be simplified into m/s, in which case you would have 61000/3600. Simplify that to 16 and 17/18. This is your meters per second, so multiply that by .724 to get the answer.