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brilliants [131]
3 years ago
14

A spherical conducting shell has charge Q. A point charge q is placed at the center of the cavity. The charge on the inner surfa

ce of the shell and the charge on the outer surface of the shell, respectively, are:
a. -q, 0
b. q, Q - q
c. 0, Q
d. -q, Q + q
e. Q, 0
Physics
1 answer:
FinnZ [79.3K]3 years ago
7 0

Answer:d

Explanation:

From Gauss law Electric field inside a surface is directly proportional to the charge enclosed in it.

Electric field inside a spherical shell is zero and hence there is no charge inside the spherical shell because q charge induces a -q charge on inside surface of spherical shell.

and to counter it there is q charge on the surface. So total charge outside the surface is Q+q

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Salsk061 [2.6K]

Answer:

Flux is 21 Nm^2/C.

Explanation:

Electric field, E = 6 N/C along X axis

Electric filed vector, E = 6 i N/C

Area, A = 4 square meter

Area vector

\overrightarrow{A} = 4 (cos30 \widehat{i} + sin 30 \widehat{j})\\\\\overrightarrow{A} = 3.5 \widehat{i} + 2 \widehat{j}\\

The flux is given by

\phi= \overrightarrow{E}.\overrightarrow{A}\\\\\phi = 6 \widehat{i} .  \left (3.5 \widehat{i} + 2 \widehat{j}  \right )\\\\\phi = 21 Nm^2/C

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3 years ago
a boy throw a ball upward from the top of a cliff 73m high.Calculate the time in which ball will fall on the ground and the velo
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The ball rises for v/g seconds; which equals 14.7/9.8=1.5 seconds . After this time, it’s height will be:


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Answer:

Explanation:

Passion

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