Density of unit cell is mathematically expressed as
D =
![\frac{\text{Z X Atomic Weight}}{\text{Avagadro's Number X a^3}}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5Ctext%7BZ%20%20X%20Atomic%20Weight%7D%7D%7B%5Ctext%7BAvagadro%27s%20Number%20X%20a%5E3%7D%7D%20)
where, Z = number of atoms/unit cell = 4 (For FCC structure)
Atomic weight of Cu = 63.5 g
a = edge length = 351 pm = 351 X 10^-10 cm
Avagadro's number = 6.023 X 10^23
∴ Density of unit cell =
![\frac{4X63.5}{6.023X10^2^3X(351X10^-^1^0)^3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B4X63.5%7D%7B6.023X10%5E2%5E3X%28351X10%5E-%5E1%5E0%29%5E3%7D%20)
= 9.752 g/cm3
Now, for FCC structure a = √8 r
where r = radius of Cu
∴ r = a/√8 = (351 X 10^-10)/√8 = 1.24 X 10^-8 cm = 124 pm
<u>Answer:</u>
<em>The molarity of the
solution is
</em>
<em></em>
<u>Explanation:</u>
The Balanced chemical equation is
![1AgNO_3 (aq) +1KCl (aq) > 1 AgCl (s)+1KNO_3 (aq)](https://tex.z-dn.net/?f=1AgNO_3%20%28aq%29%20%2B1KCl%20%28aq%29%20%3E%201%20AgCl%20%28s%29%2B1KNO_3%20%28aq%29)
Mole ratio of
: KCl is 1 : 1
So moles
= moles KCl
![Moles KCl = \frac {mass}{molarmass}](https://tex.z-dn.net/?f=Moles%20KCl%20%3D%20%5Cfrac%20%7Bmass%7D%7Bmolarmass%7D)
![= \frac {0.785 mg}{(39.1+35.5 g per mol)}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%20%7B0.785%20mg%7D%7B%2839.1%2B35.5%20g%20per%20mol%29%7D)
![= \frac {0.000785 g}{74.6 g per mol}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%20%7B0.000785%20g%7D%7B74.6%20g%20%20per%20mol%7D)
![= 0. 0000105 mol KCl](https://tex.z-dn.net/?f=%3D%200.%200000105%20mol%20KCl)
![= 0.0000105 mol AgNO_3](https://tex.z-dn.net/?f=%3D%200.0000105%20mol%20AgNO_3)
So Molarity
![= \frac {moles of solute}{(volume of solution in L)}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%20%7Bmoles%20of%20solute%7D%7B%28volume%20of%20solution%20in%20L%29%7D)
![= \frac {0.0000105 mol}{26.2 mL}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%20%7B0.0000105%20mol%7D%7B26.2%20mL%7D)
= 0.000402M or mol/L is the Answer
(Or)
is the Answer
Answer:
B, adding an indicator to a solution to test its acidity
Explanation:
Answer: B) -4819 kJ
Explanation:
The balanced reaction for combustion of octane is:
![\Delta H^0_{rxn}=-11018kJ](https://tex.z-dn.net/?f=%5CDelta%20H%5E0_%7Brxn%7D%3D-11018kJ)
To calculate the number of moles, we use the equation:
given mass of octane = 100.0 g
Molar mass of octane = 114.33 g/mol
Putting in the values we get:
![\text{Number of moles}=\frac{100.0g}{114.33g/mol}=0.8747moles](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20moles%7D%3D%5Cfrac%7B100.0g%7D%7B114.33g%2Fmol%7D%3D0.8747moles)
According to stoichiometry:
2 moles of octane give heat = -11018 kJ
Thus 0.8747 moles of octane give =
Thus -4819 kJ of heat is released by 100.0 g of octane assuming complete combustion.
Answer:
A) 1
B) 2.5
C) 3.32
Explanation:
The possibility of n=1 is not achievable in 20 minutes and 30 minutes as calculated n=1 for 10 minutes. The same conversion cannot be achieved for the rest of the time which is impossible as 75% conversion and it cannot be achieved at 10 min and 20 min at the same time
A) what is the order of the reaction if it takes 10 minutes to reach 75% conversion
= n ( order ) = 1
B) what is the order of reaction if it takes 20 minutes to reach 75% conversion
= n ( order ) ≈ 2.5
C) what is the order of reaction if it takes 30 minutes to reach 75% conversion
= n ( order ) ≈ 3.32
attached below is a detailed solution