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ohaa [14]
3 years ago
14

How are radar and an approaching siren different? How are they similar?

Chemistry
1 answer:
Irina-Kira [14]3 years ago
4 0

Answer:

b

Explanation:

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What mass of O2 is needed to produce 4.5 moles of CO2?
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Answer:

Explanation:

45

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11 Which compound has the greatest percent composition by mass of sulfur?(1) BaS (3) MgS
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Percent composition by mass is calculated (mass of element within compound)/(mass of compound)*100. The lower the total molar mass of the compound, the greater the percent composition of sulfur. In this case, MgS would be that compound, since Mg has the lowest molar mass of the four elements bonded to S.
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Naturally occurring gallium is a mixture of isotopes
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It is b have a great rest of your day
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When 2.5 grams react, the will produce how many grams of reactant in a complete chemical reaction?
const2013 [10]

Answer:

2.5g

Explanation:

When the reaction goes into completion, they will produce 2.5g. This is complement the law of conservation of mass.

According to the law of conservation of mass "in a chemical reaction, matter is neither created nor destroyed but transformed from one form to another".

  • The mass of reactants and products in a chemical reaction must be the same.
  • There is no change in mass in moving from reactant to product
  • So, if we start with 2.5g of reactants, we must end with 2.5g of products.
5 0
3 years ago
The NaCl crystal structure consists of alternating Na⁺ and Cl⁻ ions lying next to each other in three dimensions. If the Na⁺ rad
Yuliya22 [10]

Answer : The radii of the two ions Cl⁻ ion and Na⁺ ion is, 181 and 102 pm respectively.

Explanation :

As we are given that the Na⁺ radius is 56.4% of the Cl⁻ radius.

Let us assume that the radius of Cl⁻ be, (x) pm

So, the radius of Na⁺ = x\times \frac{56.4}{100}=(0.564x)pm

In the crystal structure of NaCl, 2 Cl⁻ ions present at the corner and 1 Na⁺ ion present at the edge of lattice.

Thus, the edge length is equal to the sum of 2 radius of Cl⁻ ion and 2 radius of Na⁺ ion.

Given:

Distance between Na⁺ nuclei = 566 pm

Thus, the relation will be:

2\times \text{Radius of }Cl^-+2\times \text{Radius of }Na^+=\text{Distance between }Na^+\text{ nuclei}

2\times x+2\times 0.564x=566

2x+1.128x=566

3.128x=566

x=180.9\approx 181pm

The radius of Cl⁻ ion = (x) pm = 181 pm

The radius of Na⁺ ion = (0.564x) pm = (0.564 × 181) pm =102.084 pm ≈ 102 pm

Thus, the radii of the two ions Cl⁻ ion and Na⁺ ion is, 181 and 102 pm respectively.

4 0
3 years ago
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