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AlladinOne [14]
4 years ago
10

How many moles of NaCI are present in 0.75L of a 0.55M solution?

Chemistry
1 answer:
kolezko [41]3 years ago
6 0

Answer:

,4125 (or .41 if you go by sig figs)

Explanation:

M = (mol)/(L) is a formula for concentration, but we need to solve for moles, so rewrite it as

mol = (L)(M), where we can simply plug in values as follows:

# of mols = (.75L)(.55M) = .4125mol NaCl

The question has 2 significant figures, so you could also put .41 mol NaCl

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Answer:

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Explanation:

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2 years ago
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3 years ago
The two main products of the combustion of gasoline in an automobile engine are
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4 0
3 years ago
Read 2 more answers
g In Part 7, the [Cl-] in saturated NaCl is 5.4 M at room temperature. Assume that you had 1.00 ml of the saturatedsolution, and
trapecia [35]

Answer:

7.60 M

Explanation:

Our method to solve this question is to  use the definition of molarity (M) concentration which is the number of moles per liter of solution, so for this problem we have

[Cl⁻] = # mol Cl⁻ / Vol

Now the number of moles of Cl⁻ will be sum of Cl in the 1.00 mL 5.4 M solution plus the moles of Cl⁻ in the 0.50 mL 12 M H . Since the volume in liters times the molarity gives us the number of moles we will have previous conversion of volume to liters for units consistency:

1mL x 1 L / 1000 mL = 0.001 L

0.5 mL x 1L/1000 mL = 0.0005 L

[Cl⁻]  =  0.001 L x 5.4 mol/L + 0.0005L x 12 mol/L / ( 0.001 L + 00005 L )

= 7.6 M

This is the same as the statement given in the question.

5 0
3 years ago
A piper delivers 9.98 g of water at 19 degrees Celsius. What does the pipet deliver
leva [86]

Answer:

the volume = 9.99 ml

Explanation:

in your Q we need to calculate the volume does the pipet deliver so , we are going to use this formula:

the volume = mass / density

here we need to know the density of water at a certain temperature 19 degrees Celsius ,so I used an external source   to get the density of water at 19 degrees Celsius because it is changing with different temperatures

where mass here = 9.98 g

and  the density of water at  temperature 19 degrees Celsius=  0.998405mL

-1

by substitution :

the volume = 9.98 g / 0.998405mL

-1

                   ≅ 9.996 ml = 10 ml

5 0
3 years ago
Read 2 more answers
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