Answer:
σ -> 2sp²
π -> 2p
Explanation:
The carbon has valence shell 2s 2p, and, both of them make 3 σ bonds and 1 π bond. The π bond only occurs in multiple bonds.
The σ bonds happen at the hybrids orbitals, which are orbitals formed by the association of the pure orbitals (s, p, d, f). The hybridization occurs to make possible to the atom to do the bonds because the electrons need to be isolated in it.
On the other hand, the π bonds only occur at pure orbitals. The subshell s only has 1 orbital, and the subshell p has 3 orbitals. So, because there are 3 σ bonds, it's necessary 3 hybrids orbitals (1 of s + 2 of p).
The σ bonds happen at the orbital 2sp² and the π bond at the 2p pure orbital.
Answer:
paramagnetic
Explanation:
The complex ion is : [Cr(CN)₆]³⁻
Oxidation state of Cr in [Cr(CN)₆]³⁻ is:
x + (-1)6 = -3
x = +3
CN⁻ is a strong field ligand which can result in pairing of the electrons.
The electronic configuration of Cr is:
1s²2s²2p⁶3s²3p⁶3d⁵4s¹
The electronic configuration of Cr³⁺ is:
1s²2s²2p⁶3s²3p⁶3d³
<u>These 3 electrons will be singly present in the 3 degenerate t₂g orbitals and per Hund's rule, pairing will not occur in the same level energy orbitals. So , no. of unpaired electrons will be 3 and the complex will be paramagnetic.</u>
It is not good conductors of electricity or heat!
Answer: <u> two hydrogen atoms and one oxygen</u> atom are removed during dehydration synthesis.
Hope this helps!
Delta E = Ef - Ei
E = energy , h = plank constant , v = frequency
h= 6.626 * 10 ^-34 j*s , T = 10 ^ 12 , v = 74 * 10 ^12 Hz , Hz = s^-1
E = ( 6.626 * 10^ -34 j*s) ( 74 * 10 ^ 12 s^ -1 ) = 4.90 * 10 ^ -20 J
Delta E = Ef - Ei
-4.90 * 10 ^ -20 J = -2.18 * 10 ^ -18J ( 1/4 ^2 - 1/x ^2)
0.0225 = 0.0625 - ( 1/x ^ 2)
0.225 - 0.0625 = - 1/ x ^ 2
- 0.0400 = - 1/x ^2 = -1 / - 0.0400 = x^2
25 = x^2
x = 5
