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8_murik_8 [283]
3 years ago
12

What contributions led to the acceptance of the heliocentric model of the solar system​

Chemistry
1 answer:
Alik [6]3 years ago
6 0

Answer:

It was just on a way and scienticts cant really "delete" it from galaxy so they descided accepting it and study it.

Explanation:

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Consider a mixture of soil and water and compare it to a colloid, such as milk. Which property best differentiates these two mix
antoniya [11.8K]
Milk is colloid while soil and water is a heterogeneous mixture and is a suspension mixture.
6 0
3 years ago
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Which of the following are properties of solution?
DerKrebs [107]
Point of the graph because it’s the point
8 0
3 years ago
Which compound contains both ionic and covalent
netineya [11]
The answer is (1) CaCO3. The bond between C and O is covalent bond. And the bond between Ca2+ and CO3 2- ion is the ionic bond. So the compound CaCO3 satisfy this condition.
4 0
3 years ago
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Ascorbic acid, of vitamin c (c6h8o6), is an essential vitamin. it cannot be stored by the body and must be present in the diet.
Inessa [10]

Molecular formula of ascorbic acid is C_{6}H_{8}O_{6}

Molar mass of ascorbic acid = (6 * 12 g/mol) + (8 * 1 g/mol) + (6 * 16 g/mol) = 176 g/mol

Converting 500.0 mg of ascorbic acid to moles: We use molar mass of ascorbic acid to convert mass to moles.

500.0 mg * \frac{1 g}{1000 g} *\frac{1 mol}{176 g} =   0.00284 mol

Converting 500.0 mg of ascorbic acid to molecules: The conversion factor used is 1 mole = 6.022*10^{23} molecules

500.0 mg * \frac{1 g}{1000 mg}*\frac{1 mol}{176 g} * \frac{6.022*10^{23}molecules}{1 mol} = 1.71 * 10^{21} molecules

5 0
3 years ago
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Calculate the ΔG°' for the reaction with 3 significant figures with no label for the dimension (just the number). fructose-6-pho
seraphim [82]

Answer:

ΔG° = 1747.523

Explanation:

The parameters mentioned are;

Gibbs Free energy ΔG°

Equilibrium constant Kc

Temperature T = 37 + 273 = 310 (upon conversion to kelvin temperature)

The formular relating all three parameters is given as;

ΔG° =  -RTlnKc

Where; R = rate constant = 8.314 J⋅K−1⋅mol−1

Upon solving;

ΔG° = - 8.314 * 310 * ln(1.97)

ΔG° = 1747.523

6 0
3 years ago
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