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aev [14]
3 years ago
12

Calculate the ΔG°' for the reaction with 3 significant figures with no label for the dimension (just the number). fructose-6-pho

sphate → glucose-6-phosphate. Given the equilibrium constant is 1.97 and the physiological relevant temperature is 37° C.
Chemistry
1 answer:
seraphim [82]3 years ago
6 0

Answer:

ΔG° = 1747.523

Explanation:

The parameters mentioned are;

Gibbs Free energy ΔG°

Equilibrium constant Kc

Temperature T = 37 + 273 = 310 (upon conversion to kelvin temperature)

The formular relating all three parameters is given as;

ΔG° =  -RTlnKc

Where; R = rate constant = 8.314 J⋅K−1⋅mol−1

Upon solving;

ΔG° = - 8.314 * 310 * ln(1.97)

ΔG° = 1747.523

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#8).
For this one, you have to know that every 36 inches makes 1 yard.

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That's division.
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#9).
For this problem, you have to know how to handle a mixed number,
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Add up the distances that Omar ran:

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   (4,125 meters) / (1,000 meters)  =  <em>4.125 kilometers</em>


4 0
3 years ago
Would nitrogen gas be a mineral if it has a chemical formula of n2?
STALIN [3.7K]

<u>Answer:</u>

Nitrogen gas be a mineral only, if it is in organic forms.

<u>Explanation:</u>

Most of the forms of organic nitrogen is not be taken by plants, with the exception in the form of small organic molecules. Also plants can promptly take the nitrogen  when it is in other forms like ammonia and nitrate.

The microorganisms  in the soil converts the organic forms of nitrogen to mineral form when they decompose organic matters and  also fresh plant residues. This type of process is called mineralisation.

6 0
3 years ago
Thermal expansion occurs when particles of matter move farther apart as temperature increase. True or false ?
IceJOKER [234]

Answer:

true

Explanation:

3 0
2 years ago
Select all statements that are correct:____
topjm [15]

Answer:

A, C and D are correct.

Explanation:

Hello.

In this case, since the relationship between the vapor pressure of a solution is directly proportional to the mole fraction of the solvent and the vapor pressure of the pure solvent as stated by the Raoult's law:

P_{vap}^{solution}=x_{solvent}P_{solvent}

Since the solute is not volatile, the mole fraction of the solute is not taken into account for vapor pressure of the solution, therefore A is correct whereas B is incorrect.

Moreover, since the higher the vapor pressure, the weaker the intermolecular forces due to the fact that less more molecules are like to change from liquid to vapor and therefore more energy is required for such change, we can evidence that both C and D are correct.

Best regards.

4 0
3 years ago
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