Answer:
X = 5
Explanation:
The molar ratio of water to copper(II) sulfate must be found.
The mass of water that must have been eliminated from the salt is found by the difference in weight before and after:
(500 g) - (320 g) = 180 g water eliminated
The moles of water (MW 18.02 g/mol) is then found:
(180 g) / (18.02g/mol) = 9.9889...mol
The mass of the dehydrated copper(II) sulfate (MW 159.609 g/mol) is converted to moles:
(320 g) / (159.609 g/mol) = 2.004899...mol
The molar proportion of water to the copper(II) sulfate is then calculated:
(9.9889...mol H₂O) / (2.0034899...mol CuSO₄) ≅ 5
In Chemistry, a reactivity series of metals , also known as the activity series refers to the arrangement of metals in the descending order based upon their reactivity .
<u>Salient Features</u> :-
- The metal at the top of the reactivity series are powerful reducing agents since they are easily oxidized.
- The reducing ability of metals grows weaker while traversing down the series.
- The electro-positivity of metals also reduces while moving down the reactivity series.
- Metals that are placed higher on the reactivity series have the ability to displace metals that are placed lower in the series.
<u>The metal reactivity series is given below</u> :-
To access the reactivity of metal , from the given reactivity series identify any of the metal and locate the reactivity based upon the choice of reactivity. The metal at the top (Potassium) is most reactive and the metal at the bottom (Platinum) is the least reactive.
To learn more about metal reactivity series visit -
brainly.com/question/16072297
The a answer to the statement is between B and D
Answer:
over 10 weeks the plant will grow 24 time longer than the the same hieght of the plant and the plant age will become 45 and so the plant is very much give hey man is my answer corecct
Explanation:
Answer: 3.72 M
Explanation:
Expression for rate law for first order kinetics is given by:

where,
k = rate constant = 
t = age of sample = 15.0 minutes
a = let initial amount of the reactant = 10.0 M
a - x = amount left after decay process = ?




The concentration of
in a solution after 15.0 minutes have passed is 3.72 M