The number of mole of ethanol present in the sample is 0.005 mole
<h3>Description of mole </h3>
The mole of a substance is related to it's mass and molar mass according to the following equation
Mole = mass / molar mass
With the above formula, we can obtain the mole of ethanol
<h3>How to determine the mole of ethanol</h3>
- Mass of ethanol = 0.2301 g
- Molar mass of ethanol = 46 g/mol
- Mole of ethanol = ?
Mole = mass / molar mass
Mole of ethanol = 0.2301 / 46
Mole of ethanol = 0.005 mole
Complete question
A sample of ethanol (C2H6O) has a mass of 0.2301 g. Complete combustion of this sample causes the temperature of a bomb calorimeter to increase by 1.33°C. The calorimeter has a mass of 2.000 kg and a specific heat of 2.45 J/g•°C. How many moles of ethanol are present in the sample?
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Answer:
69.55 (w/w) %
Explanation:
When NaHCO3 reacts with an acid HA, the reaction that occurs is:
NaHCO3 + HA → H2O + NaA + CO2
<em>Where 1 mole of NaHCO3 produce 1 mole of CO2</em>
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Thus, we need to convert the mass of CO2 to moles using its molar mass (44g/mol). Then, based on the chemical equation, moles of CO2 produced are equal to moles of NaHCO3 in the mixture. With its molar mass -84g/mol- we can find the mass of NaHCO3 and mass percent:
<em>Moles CO2:</em>
0.561g * (1mol / 44g) = 0.01275 moles CO2 = Moles NaHCO3.
<em>Mass NaHCO3:</em>
0.01275 moles * (84g/mol) = 1.071g NaHCO3
<em>Mass percent:</em>
1.071g NaHCO3 / 1.54g sample * 100
<h3>69.55 (w/w) %</h3>
Answer:
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Explanation:
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Answer:
Explanation:
We can use the specific heat formula, which is:
Where <em>q</em> is the energy, <em>m</em> is the mass, <em>c</em> is the specific heat capacity, and ΔT is the change in temperature.
We know the mass is 250 grams. The specific heat capacity of water is 4.18 joules per gram degree Celsius. Let's find the change in temperature.
- ΔT = final temperature - initial temperature
Now we know all the values:
Substitute the known values into the formula.
Multiply the first 2 numbers together. The grams will cancel out.
Multiply again. This time the degrees Celsius will cancel out.
The energy needed is <u>80, 465 Joules.</u>