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SVETLANKA909090 [29]
3 years ago
9

During a race, a sprinter increases from 5.0 m/s to 7.5 m/s over a period of 1.25 s. What is the sprinter’s average acceleration

during this period? _____m/s/s
Physics
2 answers:
Diano4ka-milaya [45]3 years ago
7 0

acceleration is the rate of change of velocity

the speed has increased from 5 m/s to 7.5 m/s over a period of 1.25 s

the formula to calculate acceleration is as follows

a = \frac{v-u}{t}

where a - acceleration

u - initial velocity

v - final velocity

t - time

substituting the values in the equation

a = \frac{7.5 m/s - 5.0 m/s}{1.25 s} = \frac{2.5}{1.25} = 2


acceleration is 2 m/s²

ANTONII [103]3 years ago
3 0
Acceleration = Change in Velocity/Time taken
                      = 2.5/1.25
                       = 2m/s^2 (or 2m/s/s)
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4 years ago
A hockey puck oscillates on a frictionless, horizontal track while attached to a horizontal spring. The puck has mass 0.160 kg a
marshall27 [118]

Explanation:

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          \omega = \sqrt{\frac{{k}{m}}

    \omega = \sqrt{\frac{{8}{0.160}}

    \omega = 7.07 rad/sec

(a) Formula to calculate the amplitude is as follows.

            \nu_{max} = A \omega

                  A = \frac{\nu}{\omega}

                      = \frac{0.35}{7.07}

                      = 0.05 m

Hence, value of amplitude is 0.05 m.

(b)   Displacement = 0.030 m

Formula for mechanical energy is as follows.

            M.E = \frac{1}{2}kA^{2}

Putting the values into the above formula as follows.

            M.E = \frac{1}{2}kA^{2}

                   = \frac{1}{2} \times 8 \times (0.05)^{2}

                   = 9.8 \times 10^{-3} Joule

For x = 0.03,

As,     P.E = \frac{1}{2} \times kx^{2}

                = \frac{1}{2} \times 8 \times (0.03)

                = 3.6 \times 10^{-3}

Hence, calculate the kinetic energy as follows.

            K.E = M.E - P.E

                  = (9.8 \times 10^{-3} - 3.6 \times 10^{-3}) J

                  = 6.2 \times 10^{-3} J

Thus, we can conclude that kinetic energy of the puck when the displacement of the glider is 0.0300 m is 6.2 \times 10^{-3} J.

7 0
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Read 2 more answers
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hammer [34]
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Magnitude = √(1.5² + (-3)²)
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