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oksano4ka [1.4K]

3 years ago

14

Draw the vector C⃗ =1.5A⃗ −3B⃗ .

1 answer:

hammer [34]3 years ago

8 0

If A is the measurement in the x-axis and B is the direction in the y-direction,

Magnitude = √(1.5² + (-3)²)
Magnitude = 3.35 units

Direction:
tan∅ = y/x
tan∅ = 3/1.5
∅ = 63.4°
Tan is negative in the second and fourth quadrants, and the values of x and y indicate that it is in the fourth quadrant. Therefore, the direction is 63.4° below the positive x-axis.

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A car accelerates from rest at a constant rate of 3.5m/s^2. What is the velocity of the car 12s later?

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The position of a particle moving on x-axis is given by x(t)=t^2 + 2, it’s average velocity in the final interval from t=1 to t=

san4es73 [151]

Answer:

The average velocity is 2 m/s.

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The velocity of the particle is the time derivative of its position $x(t):$

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4 years ago

The latent heat of vaporization for water at room temperature is 2430 J/g.

alukav5142 [94]

Answer:

1) $kinectic energy=7.26*10^-^2^0J$

2) $V= 2.0m/s$

3) $T=3.5*10^3K$

4) The Molecules do not burn because of the presences of hydrogen bond in place

Explanation:

From the question we are told that

latent heat of vaporization for water at room temperature is 2430 J/g.

1)Generally in determining the molar mass of water evaporated we have that

-One mole (6.02 x 10. 23 molecules)

-Molar mass of water is 18.02 g/mol

Mathematically the mass of water is give as

$M=\frac{18.02}{6.02*10^-^2^6}$

$M=3*10^-^2^3g$

Therefore

$kinectic energy=2430J/g*3*10^-^2^3g$

$kinectic energy=7.26*10^-^2^0J$

b)Generally the evaporation speed V is given as $V= \sqrt{\frac{K.E*2}{m} }$

Mathematically derived from the equation

$\frac{1}{2} mv^2 =K.E$

To Give

$V= \sqrt{\frac{K.E*2}{m} }$

$V= \sqrt{\frac{7.26*10^-^2^0J*2}{3*10^-^2^3g} }$

$V= 2.0m/s$

c)Generally the equation for velocity $Vrms=\sqrt{\frac{3RT}{M} }$

Therefore

Effective temperature T is given by

$T=\frac{\sqrt{v}*m}{R}$

where

$T=\frac{\sqrt{2.0m/s}*6.02*10^-^2^6}{0.082057 L atm mol-1K-1}$

$T=3.5*10^3K$

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