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Artemon [7]
3 years ago
15

Pain... physical, mental, emotional?

Physics
1 answer:
Rina8888 [55]3 years ago
5 0
Will you please mark me as brainliest or thank me. i can’t post a question until someone does and i’m so confused on my question i really need you to please
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What is the prefix for oxygen in As2O5? tri- di- mono- penta-
ikadub [295]
The prefix for oxygen in As2O5 is PENTA. 
Penta is used to show that the number of oxygen atoms present in the compound is five. Penta means five, while mono mean one, di means two, tri means three and tetra mans four and so on. The chemical name for the given compound is Arsenic pentoxide.
3 0
3 years ago
Read 2 more answers
An atom of uranium 238 emits an alpha particle (an atom of He) and recoils with a velocity of 1.895 * 10^ 5 m/sec . With velocit
lora16 [44]

<u>Answer:</u> The velocity of released alpha particle is 1.127\times 10^7m/s

<u>Explanation:</u>

According to law of conservation of momentum, momentum can neither be created nor be destroyed until and unless, an external force is applied.

For a system:

m_1v_1=m_2v_2

where,

m_1\text{ and }v_1 = Initial mass and velocity

m_2\text{ and }v_2 = Final mass and velocity

We are given:

m_1=238u\\v_1=1.895\times 10^{5}m/s\\m_2=4u\text{ (Mass of }\alpha \text{ -particle)}\\v_2=?m/s

Putting values in above equation, we get:

238\times 1.895\times 10^5=4\times v_2\\\\v_2=\frac{238\times 1.895\times 10^5}{4}=1.127\times 10^7m/s

Hence, the velocity of released alpha particle is 1.127\times 10^7m/s

4 0
3 years ago
Ignoring air resistance and the little friction from the plastic tube, the magnet was a freely-falling object in each trial. If
horsena [70]

Answer:

emf will also be 10 times less as compared to when it has fallen 40 \mathrm{m}

Explanation:

We know, from faraday's law-

e m f=-N \frac{\Delta \Phi}{\Delta T}

and \Phi=B . A

So, as the height increases the velocity with which it will cross the ring will also increase. (v=\sqrt{2 g h})

Given

\mathrm{V} 1(\text { Speed at } 40 \mathrm{m})=2 \mathrm{x} \mathrm{V} 2(\text { speed at } 10 \mathrm{m})

\sqrt{2 g h_{2}}=2 \times \sqrt{2 g h_{1}}=28.28 \mathrm{m} / \mathrm{s}

Now, from 40 \mathrm{cm}

V_{3}=\sqrt{2 g h_{3}}=\sqrt{2 \times 10 \times 0.4}=2.82 \mathrm{m} / \mathrm{s}

From equation a and b we see that velocity when dropped from 40 \mathrm{m} is 10 times greater when height is 40 \mathrm{cm} so, emf will also be 10 times less as compared to when it has fallen 40 \mathrm{m}

4 0
3 years ago
Question 3. AP PHYSICS. Currently learning about torque so I assume you apply torque. I don't get it at all
8090 [49]

wow that is confusing


8 0
3 years ago
Which statement describes why ocean currents are considered convection currents?
Nataly_w [17]

I think its B B)Warm water rises and cold water moves in to replace it.

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