A) We balance the masses: 4(1.00728) vs 4.0015 + 2(0.00055)4.02912 vs. 4.0026This shows a "reduced mass" of 4.02912 - 4.0026 = 0.02652 amu. This is also equivalent to 0.02652/6.02E23 = 4.41E-26 g = 4.41E-29 kg.
b) Using E = mc^2, where c is the speed of light, multiplying 4.41E-29 kg by (3E8 m/s)^2 gives 3.96E-12 J of energy.
c) Since in the original equation, there is only 1 helium atom, we multiply the energy result in b) by 9.21E19 to get 3.65E8 J of energy, or 365 MJ of energy.
P always P because P is an awkward Dorian letter that can always be trusted
Answer:
maximum speed of the elevator is 6.54 m/s
Explanation:
given,
force exerted on the elevator is 1.59 times passenger weight.
when the elevator accelerates upward with rate of a.
total force
F = m × (a+g)
1.59× mg = ma + mg
0.59 mg = ma
a = 0.59 g
we also have that
=
= 6.54 m/s
maximum speed of the elevator is 6.54 m/s
