Answer:
Straight line parallel to time axis.
Explanation:
The slope of the position time graph gives the velocity.
As the man is still, that means the velocity is zero. So, the slope of the graph is zero. It is a straight line parallel to time axis.
A person pushes a large 42.9 kg box at a constant velocity of 9 m/s across a horizontal floor for 3.8 s. Find the
1 answer:
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To develop this problem, it is necessary to apply the concepts related to the description of the movement through the kinematic trajectory equations, which include displacement, velocity and acceleration.
The trajectory equation from the motion kinematic equations is given by
Where,
a = acceleration
t = time
= Initial velocity
= initial position
In addition to this we know that speed, speed is the change of position in relation to time. So
x = Displacement
t = time
With the data we have we can find the time as well
With the equation of motion and considering that we have no initial position, that the initial velocity is also zero then and that the acceleration is gravity,
Therefore the vertical distance that the ball drops as it moves from the pitcher to the catcher is 1.46m.
Answer:
The magnitude of F₁ is 3.7 times of F₂
Explanation:
Given that,
Time = 10 sec
Speed = 3.0 km/h
Speed of second tugboat = 11 km/h
We need to calculate the speed
The force F₁is constant acceleration is also a constant.
We need to calculate the acceleration
Using formula of acceleration
Similarly,
For total force,
The speed of second tugboat is
We need to calculate total acceleration
We need to calculate the acceleration a₂
We need to calculate the factor of F₁ and F₂
Dividing force F₁ by F₂
Hence, The magnitude of F₁ is 3.7 times of F₂