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VLD [36.1K]
3 years ago
14

Calculate the final displacement from 0 if an object first moves 3 cm to the left and then 5 cm to the right.

Physics
2 answers:
antiseptic1488 [7]3 years ago
5 0
So.. if it moves 3cm to the left and 5 cm to the right, you know that it takes 3cm to get it back to it's initial starting position, but it's been displaced. 
So the final displacement is 2cm to the right.
antiseptic1488 [7]3 years ago
3 0

Answer: 2 cm to the right

Explanation:

The displacement is the shortest distance between initial and final position.

It can be calculated by subtracting the initial position from final position.

Let the sign be positive for direction towards right and negative for direction towards left.

The initial position is 0.

Firstly, object moves towards left = -3 cm

Then, the object moves towards right = 5 cm

Thus, the final position of the object is = -3 cm + 5 cm = +2 cm

Displacement = final position - initial position = + 2 cm - 0 = + 2 cm

Thus, the final displacement is 2 cm to right.

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Can you please help me with these physics displacement questions? If you can only do one, that is okay
Brut [27]

#3).  Your drawing in the lower right corner is correct.  You're headed down the right road, but ran out of gas and just stopped.

Radius of the circle = 1.5 km

Circumference of the whole circle = (2·π·radius) = 9.42 km

Distance = 3/4 of the way around it = 7.07 km .

Displacement = the straight line from the West point to the North point.  The straight-line length is 2.12 km; the straight-line direction from start to finish is Northeast (45°).  I'll let you figure out why these numbers.

#4).  What if you walk 1 mile East and then 1 mile West ?  You got a good workout, and you're back home where you started !  Your distance is 2 miles, and your displacement is zero.

The whale had a good workout too.  She swam (6.9 + 1.8 + 3.7) = 12.4 km.  She's sweating and tired.  Her total distance during that workout is 12.4 km.  

Her displacement is the line from start-point to end-point.  How she got there doesn't matter, so swimming 1 km East and then swimming 1 km West cancel out, and have no effect on the displacement.

(6.9E + 1.8W + 3.7E)  =  (10.6 E) + (1.8 W) . . . That adds up to  8.8 East !  That's where she ends up.  That's her displacement ... 8.8 km East of where she started.  Since we're only talking about displacement, we don't care HOW she got there.  She might have been swimming big 20-km circles all day.  We don't know.  All we know is that she ended up 8.8 km East of where she started.


7 0
3 years ago
I need help in my physics class and show me how it’s done
Korolek [52]

If we have the angle and magnitude of a vector A we can find its Cartesian components using the following formula

A_x = |A|cos(\alpha)\\\\A_y = |A|sin(\alpha)

Where | A | is the magnitude of the vector and \alpha is the angle that it forms with the x axis in the opposite direction to the hands of the clock.

In this problem we know the value of Ax and Ay and we need the angle \alpha.

Vector A is in the 4th quadrant

So:

A_x = 6\\\\A_y = -6.5

So:

|A| = \sqrt{6^2 + (-6.5)^2}\\\\|A| = 8.846

So:

Ay = -6.5 = 8.846cos(\alpha)\\\\sin(\alpha) = \frac{-6.5}{8.846}\\\\sin(\alpha) = -0.7348\\\\\alpha = sin^{- 1}(- 0.7348)

\alpha = -47.28 ° +360° = 313 °

\alpha = 313 °

Option 4.

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