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olga55 [171]
3 years ago
7

a person Travels along a straight road for half the distance with velocity V1 and the remaining half the distance with velocity

V2 the average velocity is given by​
Physics
1 answer:
Damm [24]3 years ago
4 0

Answer: (V1+V2)/2

Explanation: This is because basically with the question they are trying to say u(initial velocity) is V1 and v(final velocity) is V2 as the journey starts off with V1 and ends with V2 so therefore we know an equation where average velocity=(u+v)/2. So here it’s (V1+V2)/2

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A spring stretches by 0.014 m when a 3.7-kg object is suspended from its end. How much mass should be attached to this spring so
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An object has an average acceleration of +6.18 m/s2 for 0.266 s . At the end of this time the object's velocity is +9.90 m/s .
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At the start of the 0.266 s, the object's speed was 8.26 m/s.

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PLEASE HELP COME UP WITH 5 MULTIPLE CHOICE QUESTIONS FROM HEALTH RELATED FITNESS AND SKILL RELATED QUESTIONS
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Answer:

1. What is not considered a cardiovascular workout?

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5 0
3 years ago
The conducting path between the right hand and the left hand can be modeled as a 9.0-cm-diameter, 140-cm-long cylinder. The aver
Crank

Answer:

The potential difference is 121.069 V

Solution:

As per the question:

Diameter of the cylinder, d = 9.0 cm = 0.09 m

Length of the cylinder, l = 40 cm = 1.4 m

Average Resistivity, \rho = 5.5\ \Omega-m

Current, I = 100 mA = 0.1 A

Now,

To calculate the potential difference between the hands:

Cross- sectional Area of the Cylinder, A = \pi (\frac{d}{2})^{2} = 6.36\times 10^{- 3}\ m^{2}

Resistivity is given by:

\rho = R\frac{A}{l}

R = \rho \frac{l}{A}

R = 5.5\times \frac{1.4}{6.36\times 10^{- 3}} = 1210.69\ \Omega

Now, using Ohm's Law:

V = IR

V = 0.1\times 1210.69 = 121.069\ V

4 0
4 years ago
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