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Answer:
Electric field on proton

Explanation:
Given that

We know that
Charge on proton

We know that
Force = Electric field x Charge
F= E x q



Electric field on proton

Answer:
The force constant is 
The energy stored in the spring is 
Explanation:
From the question we are told that
The mass of the object is 
The period is 
The period of the spring oscillation is mathematically represented as

where k is the force constant
So making k the subject

substituting values


The energy stored in the spring is mathematically represented as

Where x is the spring displacement which is given as

substituting values


Answer:
Here Strain due to testing is greater than the strain due to yielding that is why computation of load is not possible.
Explanation:
Given that
Yield strength ,Sy= 240 MPa
Tensile strength = 310 MPa
Elastic modulus ,E= 110 GPa
L=380 mm
ΔL = 1.9 mm
Lets find strain:
Case 1 :
Strain due to elongation (testing)
ε = ΔL/L
ε = 1.9/380
ε = 0.005
Case 2 :
Strain due to yielding


ε '=0.0021
Here Strain due to testing is greater than the strain due to yielding that is why computation of load is not possible.
For computation of load strain due to testing should be less than the strain due to yielding.
Answer:
Lithification is the answer.