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larisa [96]
3 years ago
11

PLZ HELP ITS A TIMED TEST!!!!!!!!!!!!!!!!

Physics
1 answer:
sergij07 [2.7K]3 years ago
7 0
Image #3 good luck!!!!!!!!!!!
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If the distance d (in meters) traveled by an object in time t (in seconds) is given by the formula d=a+bt2, the si units of a an
ss7ja [257]
Distance , d = a+bt^2

The unit of d is in meter and t is in seconds.

So the unit of a a must be meter.

Now we have unit of bt^2 is meter.

So unit of b*second^2 = meter

Unit of b = meter/second^2

So unit of a = m and unit of b = m/s^2.
8 0
3 years ago
Consider an electron with charge −e and mass m orbiting in a circle around a hydrogen nucleus (a single proton) with charge +e.
alexandr1967 [171]

Answer:

v=\sqrt{k\frac{e^2}{m_e r}}, 2.18\cdot 10^6 m/s

Explanation:

The magnitude of the electromagnetic force between the electron and the proton in the nucleus is equal to the centripetal force:

k\frac{(e)(e)}{r^2}=m_e \frac{v^2}{r}

where

k is the Coulomb constant

e is the magnitude of the charge of the electron

e is the magnitude of the charge of the proton in the nucleus

r is the distance between the electron and the nucleus

v is the speed of the electron

m_e is the mass of the electron

Solving for v, we find

v=\sqrt{k\frac{e^2}{m_e r}}

Inside an atom of hydrogen, the distance between the electron and the nucleus is approximately

r=5.3\cdot 10^{-11}m

while the electron mass is

m_e = 9.11\cdot 10^{-31}kg

and the charge is

e=1.6\cdot 10^{-19} C

Substituting into the formula, we find

v=\sqrt{(9\cdot 10^9 m/s) \frac{(1.6\cdot 10^{-19} C)^2}{(9.11\cdot 10^{-31} kg)(5.3\cdot 10^{-11} m)}}=2.18\cdot 10^6 m/s

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4 years ago
What is the time period of a simple harmonic oscillator with a mass of 0.3kg and a force constant of 5N/m?
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Answer: 6N/m

Explanation:

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Jupiter does. :) it has many storms, causing the wind
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