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nikitadnepr [17]
3 years ago
11

Why can it be difficult to demonstrate the Law of Conservation of Mass in action when a chemical reaction takes place in an open

system?
Chemistry
1 answer:
rjkz [21]3 years ago
3 0

Answer:

In simple words, in an open system, the system that has external interactions. Such interactions can take the form of information, energy, mass etc. So keeping this definition in mind, the law of conservation of mass in open system is difficult because when chemical reaction takes places things change form and some things are released as energy, That energy than escapes the system and interacts with other surrounding. This is why it is difficult to demonstrate Law of Conservation of Mass because the changes in mass due to chemical reaction cannot be accounted for properly since the lost mass (in form of energy) was lost to environment.

Whereas, in closed system, all components occur inside a closed container or something where external interactions are minimal to none so the energy lost due to chemical reaction does not escape the system thus it can be accounted for properly to demonstrate the law of conservation of Mass.

Explanation:

Too many words but should get the point across hopefully!

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When a substance dissolves, it undergoes a _____.
Anastasy [175]

The right answer is physical change.

In the general sense, dissolution is the action of dissolving something, that is to say, of decomposing it by the separation of its parts.

In chemistry, dissolution is an intimate mixture of two bodies, at least one of which is liquid.

Eg: the dissolution of sugar in the water, the sugar will pass from the solid and dry state to the dissolved state so there is a physical change. The sugar is going to be surrounded by water molecules and form hydrogen bonds, so it can be a chemical change.

5 0
3 years ago
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Given: Mg3N2 + 3 K2O → 3 MgO + 2 K3N
Finger [1]

Answer:

0.11

Explanation:

This equation is not balanced because there is an unequal amount of O's on both sides of the equation. The left hand side has 4 P's and the right hand side has 4 P's. So the P atoms are balanced. The left hand side has 2 O's and the right hand side has 10 O's.

To fix this unbalanced equation a 5 in front of the O2 on the left hand side is added to make 10 O's on both sides resulting in

P4 + 5O2 = 2P2O5

The equation is now balanced because there is an equal amount of substances on the left and the right hand side of the equation.

6 0
3 years ago
Determine which choice(s) is/are correct?
Vesna [10]

Answer:

2 and 4 so B) II and IV

Explanation:

I false ... stirring speeds up the rate of dissolution because it increases surface area . II is true , III false ... heating up speeds up the rates of dissolution , IV is true .

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3 years ago
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Which statement best compares the melting points of magnesium and sodium?
PIT_PIT [208]

A because according to electron sea theory magnesium shares two valence electrons in electron sea while sodium shares one suggesting that magnesium has stronger metallic bond than sodium so breaking metallic bond in magnesium will require more energy as compared to breaking metallic bond in sodium

4 0
2 years ago
Determine the number of particles in 0.332 g of NaCl (molar mass NaCl=58.44 g/mol).
ira [324]

Answer:

3.42×10²¹ of particles

Explanation:

To determine the number of particles we should know, that:

1 mol of anything contains 6.02×10²³ particles

Therefore we have to find out, how many moles corresponds to 0.332 g of NaCl.

The conversion is: 0.332 g / 58.44 g/mol = 0.00568 moles

The rule of three to determine the number of particles is:

1 mol of NaCl has 6.02×10²³ particles

0.00568 moles must have (0.00568 . 6.02×10²³ particles )/1 = 3.42×10²¹

8 0
3 years ago
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