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HOPE THIS HELPED!
a. 627.1 m/s
b. the rate of effusion of ethane = 1.7 faster than hexane
<h3>Further explanation
</h3>
Given
T = 200 + 273 = 473 K
Required
a. the gas speed
b. The rate of effusion comparison
Solution
a.
Average velocities of gases can be expressed as root-mean-square averages. (V rms)
R = gas constant, T = temperature, Mm = molar mass of the gas particles
From the question
R = 8,314 J / mol K
T = temperature
Mm = molar mass, kg / mol
Molar mass of Ethane = 30 g/mol = 0.03 kg/mol
b. the effusion rates of two gases = the square root of the inverse of their molar masses:
M₁ = molar mass ethane =30
M₂ = molar mass hexane = 86
the rate of effusion of ethane = 1.7 faster than hexane
Ba(OH)₂ + 2HCl = BaCl₂ + 2H₂O
n(HCl)=c(HCl)v(HCl)
n{Ba(OH)₂)}=c{Ba(OH)₂}v{Ba(OH)₂}=2n(HCl)=2c(HCl)v(HCl)
v{Ba(OH)₂}=2c(HCl)v(HCl)/c{Ba(OH)₂}
v{Ba(OH)₂}=2*0.250*0.020/0.100=0.100 L = 100 mL
The proton is the positively charged sub-atomic particle in the nucleus of an atom and the electron is the negatively charged P for positive.
Answer:
a. MgO(s) + H2CO3(aq) → MgCO3(s) + H2O(l) DOUBLE DISPLACEMENT REACTION.
b. 2KNO3(s)→2KNO2 (s) + O2(8) DESCOMPOSITION REACTION.
c. H2(g) + CuO(s) → Cu(s) + H2O(1) SINGLE DISPLACEMENT REACTION.
d. NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(1) COMBUSTION REACTION.
e. H2(8) + Cl2(g) → 2HCl(8) SYNTHESIS REACTION.
f. SO3(g) + H2O(1)→ H2SO4(aq) SYNTHESIS REACTION.