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2 years ago

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Fill in the blanks (Balancing chemical reactions)BRAINLIEST

1 answer:

Artemon [7]2 years ago

7 0

$\huge{ \mathfrak{ \underline{ Answer \: \: ✓ }}}$

The 2 in front of $Na$ in $2Na + Cl_2 \rightarrow 2NaCl$ is <u>Coefficient.</u>

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The $_2$ after $Cl_2$ in the same equation is <u>sub </u><u>script</u><u>.</u>

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There are two atoms of $Na$ in $2NaCl$

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$\mathrm{ \#TeeNForeveR}$

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$\frac{dV}{dt}=3\times \frac{12}{169}h^2\times \frac{dh}{dt}$

$45 cm^3/s=3\times \frac{12}{169}h^2\times \frac{dh}{dt}$

$\frac{dh}{dt}=\frac{45 cm^3/s\times 169}{3\times 12\times h^2}$

Putting, h = 4 cm

$\frac{dh}{dt}=\frac{45 cm^3/s\times 169}{3\times 12\times (4 cm)^2}$

$=13.20 cm/s$

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