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Fiesta28 [93]
3 years ago
13

Fill in the blanks (Balancing chemical reactions)BRAINLIEST

Chemistry
1 answer:
Artemon [7]3 years ago
7 0

\huge{ \mathfrak{  \underline{ Answer \:  \:  ✓ }}}

The 2 in front of Na in 2Na + Cl_2 \rightarrow  2NaCl is <u>Coefficient.</u>

_____________________________

The _2 after Cl_2 in the same equation is <u>sub </u><u>script</u><u>.</u>

_____________________________

There are two atoms of Na in 2NaCl

_____________________________

\mathrm{ \#TeeNForeveR}

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The heat of fusion AH, of ethyl acetate (C4H802) is 10.5 kinol. Calculate the change in entropy as when 398. g of ethy, acetate
Hitman42 [59]

<u>Answer:</u> The entropy change of the ethyl acetate is 133. J/K

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of ethyl acetate = 398 g

Molar mass of ethyl acetate = 88.11 g/mol

Putting values in above equation, we get:

\text{Moles of ethyl acetate}=\frac{398g}{88.11g/mol}=4.52mol

To calculate the entropy change for different phase at same temperature, we use the equation:

\Delta S=n\times \frac{\Delta H_{fusion}}{T}

where,  

\Delta S = Entropy change  = ?

n = moles of ethyl acetate = 4.52 moles

\Delta H_{fusion} = enthalpy of fusion = 10.5 kJ/mol = 10500 J/mol   (Conversion factor:  1 kJ = 1000 J)

T = temperature of the system = 84.0^oC=[84+273]K=357K

Putting values in above equation, we get:

\Delta S=\frac{4.52mol\times 10500J/mol}{357K}\\\\\Delta S=132.9J/K

Hence, the entropy change of the ethyl acetate is 133. J/K

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2 years ago
Why is computational chemistry important?​
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2 years ago
Be sure to answer all parts.
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The  moles of O2 are needed to react completely with 1.00 mol of C₂H₂ is 5 mol , 0.23  moles of C₂H₂ are needed to form 0.46 mol of CO₂ .

<h3>What is a Balanced Reaction ?</h3>

A balanced reaction is a reaction in which the number of atoms present in the reactants is equal to the number of atoms in the products.

It is given in the question that

the combustion of Acetylene is given by

2 H―C≡C―H + 5 O₂ → 4 CO₂ + 2 H₂O

Given moles of Acetylene = 1 mol

Moles of oxygen needed = 5 mol

as the mole fraction of Acetylene to Oxygen is 1 :5

The mole of Acetylene needed to form 0.46 mol of CO₂ is ?

mole fraction of CO₂ to Acetylene is 4:2

Therefore 0.23 moles of CO₂ is required.

To know more about Balanced Reaction

brainly.com/question/14280002

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