Answer:
Final answer is 
Step-by-step explanation:
We need to find the equation of the line that is parallel to x=6y-5 and that passes through (5,-3).
So first we need to find the slope of given line.
rewirite x=6y-5 in y=mx+b form
x+5=6y
Compare given equation with y=mx+b
we get: m=1/6
We know that parallel equations has equal slope.
Then slope of required line m=1/6
Now plug the given point (5,-3) and slope m=1/6 into point slope formula:
Now we need to rewrite that equation in standard form. Ax+By=C.
6y=x-23
x-23=6y
x-6y=23
Hence final answer is
Answer:
f(x)=8*(3.5)^x
Step-by-step explanation:
2=98
3= 98r
4= 98r^2
5= 98r^3
6= 98r^4
98r^4/98, 98 crosses out and its just r^4. r^4= 14706.125/98
r=3.5
So you plug that in and you get f(x)=8*(3.5)^x
I hope this helped. XD
Answer:
Step-by-step explanation:
Given the formula for calculating the distance travelled expressed as;
s=1/2at^2
Given
a = 3
t = 10
Required
lower bound of s
Substitute the given values into the equation;
s=1/2at^2
S = 1/2(3)(10)^2
S = 1/2 * 3 * 100
S = 3 * 50
S = 150
Hence the lower bound of distance S is 150
Answer:
24cm^2
Step-by-step explanation:
A=bh
a=base x height..
8 x 3=24cm (^2 because its area)
