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erastova [34]
3 years ago
7

Which element was first discovered in space before it was discovered on Earth?

Chemistry
2 answers:
Tpy6a [65]3 years ago
8 0
Helllllooo Friend __________________________:-) :-):-) :-)


©©©©©here is your answer©©©©©



Helium is named from the Greek helios, "the Sun", where the element was discovered through spectroscopy.





Hope this answer help you!!!!!!!!!!! :-) :-) :-) :-) :-) :-)
faltersainse [42]3 years ago
7 0
Helium was first discovered in space before it was on earth
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During chemical cycling, inorganic nutrients are typically returned to the soil by:.
11Alexandr11 [23.1K]
Decomposers. They help break apart and digest dead matter and put those nutrients back into the soil, making them available. Happy to help!
3 0
2 years ago
How many moles of glucose, C H O , can be "burned" biologically when 18.2 mol of oxygen is available? C H O (s) + 6O (g) --->
Feliz [49]
Answer:
              547.7 g of C₆H₁₂O₆

Solution:
               The balance chemical equation is as follow,

                           C₆H₁₂O₆  +  6 O₂    →    6 CO₂  +  6 H₂O

According to equation,

                         6 moles of O₂ burns  =  180.56 g of C₆H₁₂O₆
So,
                18.2 moles of O₂ will burn  =  X g of C₆H₁₂O₆

Solving for X,
                      X  =  (18.2 mol × 180.56 g) ÷ 6 mol

                      X  =  547.7 g of C₆H₁₂O₆
5 0
3 years ago
Read 2 more answers
Suppose a student titrates a 10.00-ml aliquot of saturated ca(oh)2 solution to the equivalence point with 16.08 ml of 0.0199 m h
Alborosie
Following chemical reaction is involved upon titration of Ca(OH)2 with HCl,
Ca(OH)2 + 2HCl ↔ CaCL2 + 2H2O

Above is an example of acid-base titration to generate salt and water. Here, H+ ions of acid (HCl) combines with OH- (ions) of base [Ca(OH)2] to generated H2O

Given,
concentration of HCl = 0.0199 M
Total volume of HCl consumed during titration = 16.08 mL = 16.08 X 10^(-3) L

∴, number of moles of H+ consumed = Molarity X Vol. of HCl (in L)
                                                           = 0.0199 X 16.08 X 10^(-3)
                                                           = 3.1999 X 10^-4 mol
Thus, total number of moles of [OH-] ions present initial = 3.1999 X 10-4 mol
So, initial conc. [OH-] ion = 
\frac{number of moles of [OH-]}{volume of solution (L)} = \frac{3.1999 X 10^(^-^4^)}{10 X 10^(^-^3^)} = 0.03199 M
6 0
3 years ago
Do biotic factors contain cells
Keith_Richards [23]
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7 0
3 years ago
Which option best characterizes the following scenario?
Lisa [10]

Answer:

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