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motikmotik
3 years ago
15

3. Write a hypothesis that explains your inference about the acidity of the paper. How might you test your hypothesis by extendi

ng the experiment? What would you expect to see in this new experiment? (5 points) .​
Chemistry
1 answer:
vredina [299]3 years ago
8 0

Answer:

google

Explanation:

go to the plus thing on your screen and search it. (please dont attack me im doing a dare  >:( )

You might be interested in
Is wastewater physical properties or chemical
Leviafan [203]

its properties I know it is


hope it help ;)

4 0
3 years ago
Read 2 more answers
Balance the following equation. Then, given the moles of reactant or product below, determine the corresponding amount in moles
Mrrafil [7]

Answer:

Option a → 4 mol NH₃

Explanation:

This the unbalanced reaction

NH₃  +  O₂  ⟶  N₂  +  H₂O

The balanced reaction:

4NH₃  +  3O₂  →  2N₂  +  6H₂O

4 mol of ammonia

3 mol of oxygen

2 mol of nitrogen

6 mol of water

6 0
3 years ago
The mass number of an element is equal to
klasskru [66]

Answer:

The mass number is defined as the total number of protons and neutrons in an atom.

Explanation:

8 0
3 years ago
A solution contains 0.10 m sodium cyanide and 0.10 m potassium hydroxide. solid zinc acetate is added slowly to this mixture. wh
Brrunno [24]
1) Zn(CH₃COO)₂(s) + 2KOH(aq) = Zn(OH)₂(s) + 2CH₃COOK(aq)

Ksp{Zn(OH)₂}=1.2*10⁻¹⁷

2) Zn(CH₃COO)₂(s) + 2NaCN(aq) = Zn(CN)₂(s) + 2CH₃COONa(aq)

Ksp{Zn(CN)₂}=2.6*10⁻¹³


Ksp{Zn(OH)₂}<Ksp{Zn(CN)₂}

Zn(OH)₂ precipitates first

6 0
3 years ago
What is the majority of 0.50 g of na dissolved in a 1.5 L solution
Oxana [17]

The correct answer is 0.014467 M.  

Molarity is defined as the number of moles present in a liter solution, that is, number of moles / liter solution.  

The molar mass of sodium (Na) is 23.0 g/mol

Thus, 1 mole of Na contains 23.0 g

Now, x moles of Na contains 0.50 g

Moles = 0.50 × 1 / 23.0

Moles = 0.50 / 23.0  

= 0.0217 moles of Na

Molarity = Number of moles / liters of solution

= 0.0217 / 1.5

= 0.014467 M


8 0
3 years ago
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