Answer:
El gas se calentó a 35°C
Explanation:
Para resolver este problema es necesario aplicar la Ley de Gay Lussac donde en una situación en la que un gas no modifica su volumen, su temperatura será directamente proporcional a la presión.
Podemos pensar que se describe desde la Ley de Gases Ideales donde:
P . V = n . R . T
para la situacion 1
y P . V = n . R . T para la situacion 2
Como V, n y R son constantes:
P₁ / T₁ = P₂ / T₂
250000 Pa / 25°C = 350000 Pa / T₂
T₂ = 350000 Pa . 25°C / 250000 Pa → 35°C
Answer:
Average atomic mass of X is 10.2 amu.
Explanation:
Given data:
Percentage abundance of X-10 = 80%
Percentage abundance of X-11 = 20%
Average atomic mass of X = ?
Solution:
Average atomic mass of X = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass of \X = (80×10)+(20×11) /100
Average atomic mass of X = 800 + 220 / 100
Average atomic mass of \X = 1020 / 100
Average atomic mass of X = 10.2 amu
The periodic table of elements arranges all of the known chemical elements in an informative array. Elements are arranged from left to right and top to bottom in order of increasing atomic number. Order generally coincides with increasing atomic mass. The rows are called periods.
Answer:
To convert C to K, just add 273, remember that 0° C is 273 K, so 73.a) is 317.2 K and 73.c) is 253 K. 74.a) Will be, -129, 4 C + 273 = 143.5 F, 74.c) 663.8 F
75.a) 7.2 C , 75.c) -23.3 C
Explanation:
To convert C to F, you can use this, (9/5 * C + 32 ) = F, or back ward, C = (F - 32)* 5/9.