Given :
Length , l = 59.8 m.
Breadth , b = 26.6 m.
Depth , d = 3.7 ft .
Density of water ,
.
To Find :
Mass of water in pool .
Solution :
First we will covert depth into m from ft .

For ,

So , volume of pool is :

We know , density is given by :

So , 
Putting given values in above equation :

Hence , this is the required solution.
Quantum numbers are used to describe the location of electrons in atoms.
Principal quantum number(n) tells which energy shell the electrons reside in.
The first energy shell n = 1, second energy shell n = 2 and it goes on.
Azimuthal quantum number (l) states which orbital the electron is most likely to reside in. the number of orbitals in an energy shell depends on the principal quantum number. number of orbitals are from 0 to n-1
If l = 0, s orbital
l = 1 , p orbital
l = 2, d orbital
in 2nd energy shell the number of orbitals are 0,1 etc.
5s-
Principal quantum number n = 5
Azimuthal quantum number l = 0
6p
Principal quantum number n = 6
Azimuthal quantum number l = 1
4d
Principal quantum number n = 4
Azimuthal quantum number l = 2
The calculated enthalpy values are as follows:
- Total enthalpy of reactants = -103.85 KJ/mol
- Total enthalpy of products = -2057.68 KJ/mol
- Enthalpy of reaction = -1953.83 kJ/mol
<h3>What is the enthalpy of the reaction?</h3>
The enthalpy of the reaction is determined as follows:
- Enthalpy of reaction = Total enthalpy of products -Total enthalpy of reactants
- Total enthalpy of reactants = (ΔHf of Reactant 1 x Coefficient) + (ΔHf of Reactant 2 x Coefficient)
- Total enthalpy of products= (ΔHf of Product 1 x Coefficient) + (ΔHf of Product 2 x Coefficient)
Equation of reaction equation: C₃H₈ (g) + 5 O(g) → 4 H₂O(g) + 3CO₂(g)
Total enthalpy of reactants = (-103.85 * 1) + (0 * 5)
Total enthalpy of reactants = -103.85 + 0
Total enthalpy of reactants = -103.85 KJ/mol
Total enthalpy of products = (-393.51 * 4) +(-241.82 * 3)
Total enthalpy of products = (-1574.04) + (-483.64)
Total enthalpy of products = -2057.68 KJ/mol
Enthalpy of reaction = -2057.68 KJ/mol -(-103.85 KJ/mol)
Enthalpy of reaction = -1953.83 kJ/mol
In conclusion, the enthalpy of the reaction is determined from the difference between the total enthalpy of products and reactants.
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