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Gwar [14]
2 years ago
11

Balance the equation

Chemistry
1 answer:
saveliy_v [14]2 years ago
8 0

Explanation:

3C3+2H4+9O=3CO3+4H29o

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How many kJ are 3,340J?
forsale [732]
The answer I believe is 3.340kj.
8 0
3 years ago
Question #1: Identify the type of Mutation below
borishaifa [10]

Answer:

Deletion

Explanation:

A mutation refers to a change in the DNA sequence. This means that the original sequence of bases in the DNA has been altered permanently.

There are three types of DNA mutations;  base substitutions, deletions and insertions.

In the particular case of this question, the original is TTCGATA while the copy is TTGATA. If you look closely at the two, you will notice that the C has been omitted. This is an example of  deletion.

5 0
2 years ago
Does the temperature of the solvent (water) affect the rate of dissolving?​
gregori [183]
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3 0
3 years ago
Is it possible for the equivalence point of a titration to not be at pH 7? Explain your answer.
lara31 [8.8K]
<span>The reason it will be 7 for some titrations is that when you  titrates a strong acid with a strong base for example  HCl and NaOH the salt formed is conjugate base of strong acid and will be a very weak base
 That means that it cannot produce any OH^-1 and all the H+ has been converted to water.The only source of H+ or OH is water with a Ka of 10^-14 so the pH = -log [H+]=-log 10^-7 = 7 
second reason is 
When you titrates a weak acid with strong base at equivalence point 
only a water solution of the conjugate base exists 

CH3COOH + NaOH ----- Na+ CH3COO^-1 + H2O 
Since the conjugate base is the conjugate base of a weak acid it will hydrolyze in water like so 
for instance Na+ CH3COO^-1 + HCl---- CH3COOH + NaCl the equivalence point will be way BELOW 7 and in the case of above will be less than 5. So pH of 7 at equivalence point is only reached in strong acid strong base titrations.
hope this helps</span>
5 0
3 years ago
Read 2 more answers
what is the maximum amount of moles of P2O5 that can theoretically be made from 136 g of P4 and excess oxygen
zhuklara [117]
We are given with
136 g P4
excess oxygen

The complete combustion reaction is
P4 + 5O2 => 2P2O5
Converting the amount of P4 to moles
136/123.9 = 1.098 moles

Using stoichiometry
moles P2O5 = 1.098 x 2 = 2.195 moles P2O5
6 0
3 years ago
Read 2 more answers
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