A compound is known to be Na2CO3, Na2SO4, NaOH, NaCl, NaC2H3O2, or NaNO3. When a barium nitrate solution is added to a solution
1 answer:
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Answer:
The molarity of the base is 0.2664 M
Explanation:
Firstly, we write the complete and balanced titration reaction.
+
→
+
From the reaction, we can identify that 1 mole of the acid reacted with 2 moles of the alkali (base) to yield salt and water only
We identify the following also from the question;
= 14.80 mL ,
= 25.00 mL ,
= 0.225M and
= ?
= 1 ,
= 2
We use the relation;
/
=
/
Plugging the values, we have ;
(0.225 × 14.80)/1 = ( × 25.00)/2
= (2 × 0.225 × 14.80)/25
= 0.2664 M