Answer:
614 034 kg
Explanation:
n = m/Mm
m = n * Mm
Mm(MgSO4) = 1 * 24.3 * 1 * 32.1 * 4 * 16 = 49921.92
m = 12.3 * 49921.92
m = 614 034 kg
<h3>
Answer:</h3>
1 x 10^13 stadiums
<h3>
Explanation:</h3>
We are given that;
1 stadium holds = 1 × 10^5 people
Number of iron atoms is 1 × 10^18 atoms
Assuming the stadium would carry an equivalent number of atoms as people.
Then, 1 stadium will carry 1 × 10^5 atoms
Therefore,
To calculate the number of stadiums that can hold 1 × 10^18 atoms we divide the total number of atoms by the number of atoms per stadium.
Number of stadiums = Total number of atoms ÷ Number of atoms per stadium
= 1 × 10^18 atoms ÷ 1 × 10^5 atoms/stadium
= 1 × 10^13 Stadiums
Thus, 1 × 10^18 atoms would occupy 1 × 10^13 stadiums
The question is incomplete, the complete question is;
A block is pulled 0.90 m to the right in 2.5 s. What is the blocks average speed to the nearest hundredth of a m/s
Answer:
0.36 m/s to the hundredth place
Explanation:
Now let us remember the definition of speed. Speed is defined in physics as distance/time.
Here we have the distance as 0.9 m
We have the time as 2.5 s
Hence the average speed is obtained from;
Speed = 0.9/2.5 = 0.36 m/s to the hundredth place
I don’t understand your language sorry
